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3 years ago

*R3= 9 ohms What is the voltage drop running through resistor five?

Physics

1 answer:

joja [24]3 years ago

5 0

The correct answer is: The voltage drop across $R_5$ is 45V.

Explanation:
First you need to find the total current of the circuit, which is:
According to Ohm's law:

V = I * R

I = V/R --- (1)

Where
R = Total Equivalent resistance of the circuit
V = Total Voltage = 90V
I -= Total Current

First let us find the equivalent resistance:
$R = R_1 + R_2 + R_5 + \frac{R_3*R_4}{R_3+R_4} \\
R = 3 + 6 + 15 + \frac{9*18}{9+18} \\
R = 30$

Now plug in the values in (1):
(1) => I = 90/30 = 3A

Now that we have current of the circuit, we can now find the voltage drop across $R_5$ = 15 ohms using:
$V_5 = I * R_5$

Where $V_5$ is the voltage drop across resistor 5;
$V_5 = 3 * 15 = 45V$

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4 years ago

A 782-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satelli

Vadim26 [7]

Answer:

a) v = 5.59x10³ m/s

b) T = 4 h

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Explanation:

a) We can find the satellite's orbital speed by equating the centripetal force and the gravitation force as follows:

$F_{c} = F_{G}$

$\frac{mv^{2}}{r + h} = \frac{GMm}{(r + h)^{2}}$

$v = \sqrt{\frac{gr^{2}}{r+h}$

Where:

g is the gravity = 9.81 m/s²

r: is the Earth's radius = 6371 km

h: is the satellite's height = r = 6371 km

$v = \sqrt{\frac{gr^{2}}{2r}} = \sqrt{\frac{gr}{2}} = \sqrt{\frac{9.81 m/s^{2}*6.371 \cdot 10^{6} m}{2}} = 5.59 \cdot 10^{3} m/s$

b) The period of its revolution is:

$T = \frac{2\pi}{\omega} = \frac{2\pi (r + h)}{v} = \frac{2\pi (2*6.371 \cdot 10^{6} m)}{5.59 \cdot 10^{3} m/s} = 14322.07 s = 4 h$

c) The gravitational force acting on it is given by:

$F = \frac{GMm}{(r + h)^{2}}$

Where:

M is the Earth's mass = 5.97x10²⁴ kg

m is the satellite's mass = 782 kg

G is the gravitational constant = 6.67x10⁻¹¹ Nm²kg⁻²

$F = \frac{GMm}{(r + h)^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}kg^{-2}*5.97 \cdot 10^{24} kg*782 kg}{(2*6.371 \cdot 10^{6} m)^{2}} = 1.92 \cdot 10^{3} N$

I hope it helps you!

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3 years ago

3. A large passenger ship required a force of 1,600,000 N to move 2000 m. How much work is done on the ship?

Dovator [93]

Answer:

3,200,000,000 J

Explanation:

Work is defined as the amount of energy transferred as an object is moved a certain distance with a certain force. Mathematically, we express this with the equation

$W=Fs$

where W is work (measured in joules), F is the force applied (in Newtons), and s is the distance, also called the displacement (in meters).

Here, we have F = 1,600,000 N and s = 2000 m, so our work will be

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7 0

3 years ago

An inexperienced researcher runs an experiment and sets his alpha level at .40 because he can't wait to get his firstsignificant

GuDViN [60]

A potential problem is that you are willing to accept a 5% chance of being wrong if you reject the null hypothesis.

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The smaller the value of α the more difficult it is to reject the null hypothesis. Therefore, choosing a low value for α can reduce the likelihood of Type I errors. The result here is that if the null hypothesis is false, it may be more difficult to reject using a lower value for α. The alpha value or statistical significance threshold is arbitrary. Which value to use depends on your field of study.

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1 year ago

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