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Mnenie [13.5K]
3 years ago
5

Study the motion map shown. what do the circled vectors represent?

Physics
1 answer:
BabaBlast [244]3 years ago
3 0

Answer:

It's option d - Negative acceleration

Explanation:

  • Let's start by demonstrate why <em>it's not option b - Speed : </em>Speed is a scalar quantity so it can not be represented by a vector
  • Let's check that <em>the green  vectors represent velocity</em> (velocity is a vector quantity, velocity is a direction aware, while speed is just a scalar)

  • Now let's  show that the circled vectors are acceleration vectors:

Mathematically position X , velocity V and acceleration A are:

\frac{dX}{dt} = V and \frac{dV}{dt} = A

Where X, V, A are vectors and \frac{d(a)}{dt} = b  indicates the derivate a of a time is equal to b.

So, this show that acceleration is a rate respect of time of velocity ⇒ When acceleration is positive, velocity increments, when acceleration is negative, velocity decrements.

<em>The above explanation correspond to the motion map shown, getting demonstrated that the answer is D - Negative acceleration </em>

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Let the initial speed will be v

now we will have

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in y direction

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now displacement in x direction

x = (vcos45)t + 0

displacement in y direction

y = (vsin45)t - \frac{1}{2}gt^2

now from above two equations we have

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Our milky way galaxy is 100000 lyly in diameter. a spaceship crossing the galaxy measures the galaxy's diameter to be a mere 1.
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The speed of the spaceship relative to the galaxy is 0.99999995c.

A light-year measures distance rather than time (as the name might imply). A light-year is a distance a light beam travels in one year on Earth, which is roughly 6 trillion miles (9.7 trillion kilometers). One light-year equals 5,878,625,370,000 miles. Light moves at a speed of 670,616,629 mph (1,079,252,849 km/h) in a vacuum.We multiply this speed by the number of hours in a year to calculate the distance of a light-year (8,766).

The Milky way galaxy is 100,000 light years in diameter.

The galaxy's diameter is a mere 1. 0 ly.

We know that ;

L = L_0 \sqrt{1-\frac{v^2}{c^2} }

L = 1 light year

L₀ = 100,000 light year

1 = 100,000 \sqrt{1-\frac{v^2}{c^2} }

1 = 100,000 \sqrt{1-\frac{v^2}{(3*10^8)^2} }

\frac{1}{100,000}  = \sqrt{1-\frac{v^2}{c^2} }

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Therefore, the speed of the spaceship relative to the galaxy is 0.99999995c.

Learn more about a light year here:

brainly.com/question/17423632

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