C- Stratus clouds are the rainy clouds.
Hope this helps!
The answer is oil and water. If you want I could give you the reason too
Answer:
(a). The reactive power is 799.99 KVAR.
(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.
Explanation:
Given that,
Power factor = 0.6
Power = 600 kVA
(a). We need to calculate the reactive power
Using formula of reactive power
...(I)
We need to calculate the ![\phi](https://tex.z-dn.net/?f=%5Cphi)
Using formula of ![\phi](https://tex.z-dn.net/?f=%5Cphi)
![\phi=\cos^{-1}(Power\ factor)](https://tex.z-dn.net/?f=%5Cphi%3D%5Ccos%5E%7B-1%7D%28Power%5C%20factor%29)
Put the value into the formula
![\phi=\cos^{-1}(0.6)](https://tex.z-dn.net/?f=%5Cphi%3D%5Ccos%5E%7B-1%7D%280.6%29)
![\phi=53.13^{\circ}](https://tex.z-dn.net/?f=%5Cphi%3D53.13%5E%7B%5Ccirc%7D)
Put the value of Φ in equation (I)
![Q=600\tan(53.13)](https://tex.z-dn.net/?f=Q%3D600%5Ctan%2853.13%29)
![Q=799.99\ kVAR](https://tex.z-dn.net/?f=Q%3D799.99%5C%20kVAR)
(b). We draw the power triangle
(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95
Using formula of reactive power
![Q'=600\tan(0.95)](https://tex.z-dn.net/?f=Q%27%3D600%5Ctan%280.95%29)
![Q'=9.94\ KVAR](https://tex.z-dn.net/?f=Q%27%3D9.94%5C%20KVAR)
We need to calculate the difference between Q and Q'
![Q''=Q-Q'](https://tex.z-dn.net/?f=Q%27%27%3DQ-Q%27)
Put the value into the formula
![Q''=799.99-9.94](https://tex.z-dn.net/?f=Q%27%27%3D799.99-9.94)
![Q''=790.05\ KVAR](https://tex.z-dn.net/?f=Q%27%27%3D790.05%5C%20KVAR)
Hence, (a). The reactive power is 799.99 KVAR.
(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.
Answer:
Explanation:
Given
initial velocity component of engines is
![v_0_x=6380 m/s](https://tex.z-dn.net/?f=v_0_x%3D6380%20m%2Fs)
![v_0_y=6770 m/s](https://tex.z-dn.net/?f=v_0_y%3D6770%20m%2Fs)
time period of engine running=763 s
Displacement in ![x=4.50\times 10^6](https://tex.z-dn.net/?f=x%3D4.50%5Ctimes%2010%5E6)
![y=7.27\times 10^6](https://tex.z-dn.net/?f=y%3D7.27%5Ctimes%2010%5E6)
Using
in x and y direction
![x=v_0_x\times t+\frac{at^2}{2}](https://tex.z-dn.net/?f=x%3Dv_0_x%5Ctimes%20t%2B%5Cfrac%7Bat%5E2%7D%7B2%7D)
![4.50\times 10^6=6380\times 763+\frac{a\times 763^2}{2}](https://tex.z-dn.net/?f=4.50%5Ctimes%2010%5E6%3D6380%5Ctimes%20763%2B%5Cfrac%7Ba%5Ctimes%20763%5E2%7D%7B2%7D)
![4.50\times 10^6-4.86\times 10^6=\frac{a\times 763^2}{2}](https://tex.z-dn.net/?f=4.50%5Ctimes%2010%5E6-4.86%5Ctimes%2010%5E6%3D%5Cfrac%7Ba%5Ctimes%20763%5E2%7D%7B2%7D)
![a=-1.23 m/s^2](https://tex.z-dn.net/?f=a%3D-1.23%20m%2Fs%5E2)
In y direction
![y=v_0_y\times t+\frac{a't^2}{2}](https://tex.z-dn.net/?f=y%3Dv_0_y%5Ctimes%20t%2B%5Cfrac%7Ba%27t%5E2%7D%7B2%7D)
![7.27\times 10^6=6770\times 763+\frac{a\times 763^2}{2}](https://tex.z-dn.net/?f=7.27%5Ctimes%2010%5E6%3D6770%5Ctimes%20763%2B%5Cfrac%7Ba%5Ctimes%20763%5E2%7D%7B2%7D)
![7.27\times 10^6-5.16\times 10^6=\frac{a\times 763^2}{2}](https://tex.z-dn.net/?f=7.27%5Ctimes%2010%5E6-5.16%5Ctimes%2010%5E6%3D%5Cfrac%7Ba%5Ctimes%20763%5E2%7D%7B2%7D)
![a=7.24 m/s^2](https://tex.z-dn.net/?f=a%3D7.24%20m%2Fs%5E2)
x component![=-1.23 m/s^2](https://tex.z-dn.net/?f=%3D-1.23%20m%2Fs%5E2)
y component![=7.24 m/s^2](https://tex.z-dn.net/?f=%3D7.24%20m%2Fs%5E2)