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sergejj [24]
3 years ago
14

According to the law of conservation of energy, which statement must be

Physics
1 answer:
motikmotik3 years ago
4 0

Answer:

i hope it will help you

THANK YOU

Explanation:

thank you

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An ant crawls in a straight line at a constant speed of 0.24 m/s for a distance of 3.0 m, beginning in the corner of a square cl
Talja [164]

Answer:

vavg = 0.37 m/s

Explanation:

  • The average speed is just the relationship between the total distance traveled, and the total time required for that travel , as follows:

       v_{avg} = \frac{\Delta x}{\Delta t} (1)

  • We know that for the first leg of the journey, the ant crawls at a constant speed of 0.24 m/s, moving 3.0 m.
  • We can find the time required for this part, just applying the definition of average velocity, and solving for the time t (which we will call t₁), as follows:

       t_{1} =\frac{x_{1}}{v_{1} } = \frac{3.0m}{0.24m/s} = 12.5 s (2)

  • From the givens, we know that the time for the second part is exactly the half of the value found in (2), so we can write the total time Δt as follows:

       \Delta t = t_{1} + \frac{t_{1} }{2} = 12.5 s + 6.25 s = 18.75 s (3)

  • We also know that in the second leg of the journey, the ant traveled 4.0 m, which adds to the 3.0 m of the first part, making a total distance of 7.0 m.
  • Per definition of average speed, we can write the following expression as in (1) replacing Δx and Δt by their values, as follows:

       v_{avg} = \frac{\Delta x}{\Delta t} = \frac{7.0m}{18.75m} = 0.37 m/s (4)

3 0
3 years ago
How long did it take for a message sent from earth to reach the first astronauts?
Sergeu [11.5K]

Time taken for a message to sent from earth to reach the first astronauts is  140 second.

It takes about three days for a spacecraft to reach the Moon. in the course of that time a spacecraft travels at the least 240,000 miles 386,400 km that is the space between Earth and the Moon. The specific distance depends at the specific path selected.

The distance from earth to moon is approximately3.84*108m

So, the distance from earth to the astronauts is3.84*108m - 10500*103m =3.735*108m

The speed of light c = 2.99792458*108m/s

So, divided the distance from earth to astronauts by the speed off light,

3.735*108m/2.99792458*108m/s ˜1.25seconds

Divided the Pluto-earth distance by speed of light:

Hence, 4.2*1010m/2.99792458*108m/s = 140seconds

Learn more about astronauts here:-brainly.com/question/24496270

#SPJ4

8 0
1 year ago
Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons p
boyakko [2]

Answer:

The number of free electrons per cubic meter is 7.61\times 10^{28}\ m^{-3}

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal, \sigma=6.8\times 10^7\ \Omega^{-1}m^{-1}

Density of metal, \rho=10.5\ g/cm^3

Atomic weight, A = 107.87 g/mol

Let n is the number of  free electrons per cubic meter such that,

n=1.3\ N

n=1.3(\dfrac{\rho N_A}{A})

Where

\rho is the density of silver atom

N_A is the Avogadro number

A is the atomic weight of silver

n=1.3\times (\dfrac{10.5\ g/cm^3\times 6.02\times 10^{23}\ atoms/mol}{107.87\ g/mol})

n=7.61\times 10^{22}\ cm^{-3}

or

n=7.61\times 10^{28}\ m^{-3}

Hence, this is the required solution.

6 0
3 years ago
A 2000 kg truck is traveling at 5 m/s and collides with a 1000 kg car that is not moving. After the collision, the 2000 truck st
sp2606 [1]

Answer:

A) 10 m/s

Explanation:

We know that according to conservation of momentum,

m1v1 + m2v2 = m1u1 + m2u2  ..............(equation 1)

where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.

From the given data

If truck and car are two bodies

truck :       m1 = 2000 Kg           v1 = 5 m/s                u1 = 0

car    :        m2 = 1000 kg           v2 = 0                      u2 = ?

final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.

substituting the values in equation 1, we get

(2000 x 5) + 0 = 0 + (1000 x u2)

u2 = \frac{2000}{1000} x 5

    = 10 m/s

Hence after collision, car moves at a velocity of 10 m/s

3 0
3 years ago
Aray diagram is shown.<br> Medium 2<br> Medium 1<br> Which statement best describes the diagram?
Lady bird [3.3K]

if we can't see air do fish see water ?

6 0
4 years ago
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