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2 years ago

According to the law of conservation of energy, which statement must be

Physics

1 answer:

motikmotik2 years ago

4 0

Answer:

i hope it will help you

THANK YOU

Explanation:

thank you

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Kenneth observes that as an ambulance approaches him, the pitch of the sound of the siren is higher, and the pitch decreases whe

alexgriva [62]

Answer: A.

Explanation:

Since pitch and frequency are the same thing when frequency is higher the wavelength decreases and A is the only valid answer.

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3 years ago

Should athletes be benched if their grades are too low, or should they be allowed to play anyway?

sdas [7]

They should be benched.

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2 years ago

A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b

Natasha_Volkova [10]

Answer:

Part a)

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part b)

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

Explanation:

Part a)

By Guass law we know that

$\int E. dA = \frac{q}{\epsilon_0}$

$E. 2\pi rL = \frac{\lambda L}{\epsilon_0}$

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part b)

Outside the outer cylinder we will again use Guass law

$\int E. dA = \frac{q}{\epsilon_0}$

$E. 2\pi rL = \frac{\lambda L}{\epsilon_0}$

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

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3 years ago

How much WATER needed to offset the force of jumping down from 20metre in vacuum environment,to keep me alive.

kenny6666 [7]

Answer:

it's quite difficult

Explanation:

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2 years ago

There is a 12 v potential difference between the positive and negative ends of the jumper cables, which are a short distance apa

steposvetlana [31]

The electric potential energy of the electron depends on the potential difference applied between the two ends of the cable. Indeed, the electric potential energy of a charge is given by
$U=q \Delta V$
where q is the magnitude of the charge, while $\Delta V$ is the potential difference applied. So, U depends on $\Delta V$ .

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3 years ago