Solve for p6 = 3 + 3pP=
2 answers:
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Answer:
The equation of the circle having centre (-5,-9) and radius r=3 is
x² + 10 x +y² + 14 y + 65 = 0
Step-by-step explanation:
<u>Explanation</u>:-
From graph The centre of the circle C( -5 , -7)
The radius of the circle r = 3cm from the centre of the given circle
The equation of the circle
From graph the centre ( h, k) = ( -5,-7) and r = 3cm
x² + 10 x +25 +y² + 14 y + 49 =9
x² + 10 x +25 +y² + 14 y + 49 -9=0
The equation of the circle
x² + 10 x +y² + 14 y + 65 = 0
For this case we have the following functions:
When x = 0 we have:
For y1:
For y2:
Therefore, we have to:
When x = 5 we have:
For y2:
For y3:
Therefore, we have to:
When x = -1 we have:
For y1:
For y2:
For y3:
Therefore, we have to:
Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2
When x = 0 we have:
For y1:
For y2:
Therefore, we have to:
When x = 5 we have:
For y2:
For y3:
Therefore, we have to:
When x = -1 we have:
For y1:
For y2:
For y3:
Therefore, we have to:
Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2