Answer:
50
Step-by-step explanation:
6/100=3/y
Let y be the total number of items on the test
[cross multiply]
6×y =3×100
6y = 300
divide both sides by 6
y = 50
Jason hit 11 homeruns.
Step-by-step explanation:
Homeruns hit by Nathan = 19
Let,
Homeruns hit by Nathan = x
Homerun hit by Jason = y
According to given statement;
x = 2y - 3 Eqn 1
We know that Nathan hit 19 homeruns, therefore, putting x=19 in Eqn 1

Dividing both sides by 2;

Jason hit 11 homeruns.
Keywords: linear equations, addition
Learn more about linear equations at:
#LearnwithBrainly
Answer:
414 9/16 m³

Step-by-step explanation:
The volume of a Rectangular prism is calculated as Length × Width × Height
From the attached diagram,we can see that
The length = 8 3/8 m
The width = 6 m
The height =8 1/4 m
Converting the mixed fraction to improper fraction in other to simplify it better
The length = 67/8 m
The height = 33/4 m
The volume of the rectangular prism =
67/8 m × 6m × 33/4m
= (13266/32)m³
= 6633/16 m³
= 414 9/16 m³
= 
I’m not sure about the rest but the slope is 4 and the y intercept is 3.
Answer:
(B) (0.396, 1.712)
Step-by-step explanation:
From the information given;
Confidence Interval = 0.95
Significance Level 
The confidence interval for regression coefficient beta (whereby in this case it is the coefficient of the diameter) is expressed by:
= 
From the regression coefficient, the estimated value of beta^ = 1.054

