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Zanzabum
3 years ago
13

What is 29/5as a mixed number

Mathematics
2 answers:
dimulka [17.4K]3 years ago
8 0
5 4/5 is a mixed number of 29/5.
stiv31 [10]3 years ago
7 0
29/5 as a mixed number is: 5 4/5
This is because in order to get a mixed number you first must see how many times you can get the denominator into the numerator. In this case it is 5 times since 5 x 5 is 25 but 5 x 6 is 30, which is over 29. So then we do 29 - 25 to figure out the remaining value, which is 4. We leave this over the original denominator, 5, while moving the 5 out of the fraction to the front.
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Yasmin purchased 6 heads of cabbage that each weighed 2 and StartFraction 3 over 8 EndFraction pounds. How much did the cabbage
padilas [110]

The total weight of cabbage is 14 1/4

<h3 /><h3>What is Equation?</h3>

An equation can be defined as a mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value.

Given:

Yasmin purchased 6 heads of cabbage that each weighed 2 and  3/8 pounds.

So,

2 and 3/8 = 19/8

1 cabbage = 19/8 pounds

6 cabbages = x pounds

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x = 14 2/8

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Learn more about this concept here:

brainly.com/question/18762466

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1 year ago
1/3x+1/2=5(4/5x-2) what is X equal to?
lisabon 2012 [21]
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sam raked 3 bags of leaves in 6 minutes.if he works at the same rate, about how long will it take him to rake 5 bags
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Evaluate the following pic
GREYUIT [131]

Answer:

1) \sqrt{1225}+\sqrt{1024}=67

2)  \sqrt[3]{-1331}=-11

3) Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

Step-by-step explanation:

1) \sqrt{1225}+\sqrt{1024}

Prime factors of 1225 : 5x5x7x7

Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2

\sqrt{1225}+\sqrt{1024}\\=\sqrt{5\times5\times7\times7}+\sqrt{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\=\sqrt{5^2\times7^2}+\sqrt{2^2\times2^2\times2^2\times2^2\times2^2}\\=5\times7+(2\times2\times2\times2\times2)\\=35+32\\=67

\sqrt{1225}+\sqrt{1024}=67

2) \sqrt[3]{-1331}

We know that \sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)

Applying radical rule:

\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11

So, \sqrt[3]{-1331}=-11

3) 2:p :: p:8

It can be written as:

p*p=2*8\\p^2=16\\Taking \ square \ root \ on \ both \ sides\\\sqrt{p^2}=\sqrt{16}\\p=\pm 4

Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6

Put value of x, y and z in equation and solve:

x^3+y^2+z \\=(3)^3+(-2)^2+(-6)\\=27+4-6\\=25

So, x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}

We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd

\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}\\\\=\frac{1296\times-8\times 27}{46656}\\\\=\frac{-279936}{46656} \\\\=-6

So, \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

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Answer:

SA = 2πr² + 2πrh

Step-by-step explanation:

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2πrh will provide the surface area of the cylinder portion that connects the top and bottom

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