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maks197457 [2]
3 years ago
13

If f(x) = 3x + 2 and g(x) = 2x – 2, what is (f – g)(x)?

Mathematics
2 answers:
dusya [7]3 years ago
7 0
I would assume that you subsitute as usual, but g is negative
(f-g)(x)=(3x+2)-(2x-2)
(f-g)(x)=3x+2-2x+2
(f-g)(x)=x+4
aivan3 [116]3 years ago
5 0
f(x)=3x+2 \\
g(x)=2x-2 \\ \\
(f-g)(x)=f(x)-g(x)=3x+2-(2x-2)=3x+2-2x+2=\\
=x+4 \\ \\
\boxed{(f-g)(x)=x+4}
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Muke is sick with the flu but he still cors to school on monday. He areives at 8am and by 9am (hour 1) muke has already infected
Volgvan

Answer:

\begin{array}{ccccccccc}{Hours} & {0} & {1} & {2} & {3} & {4}& {5} & {6} & {7} \ \\ {Persons} & {1} & {2} & {4} & {8} & {16}& {32} & {64} & {128} \ \end{array}

Step-by-step explanation:

Given

See attachment for complete question

Solving (a): Complete the table

Let

x = hours

y = persons

From the table question, we have:

(x_1,y_1) = (0,1)

(x_2,y_2) = (1,2)

(x_3,y_3) = (2,4)

The pattern follows that, an increment in x by doubles the value of 1.

So, the other values are:

(x_4,y_4) = (3,8)

(x_5,y_5) = (4,16)

(x_6,y_6) = (5,32)

(x_7,y_7) = (6,64)

(x_8,y_8) = (7,128)

So, the complete table is:

\begin{array}{ccccccccc}{Hours} & {0} & {1} & {2} & {3} & {4}& {5} & {6} & {7} \ \\ {Persons} & {1} & {2} & {4} & {8} & {16}& {32} & {64} & {128} \ \end{array}

Solving (b): The graph

The table follows an exponential function:

y = ab^x

We have: (x_1,y_1) = (0,1)

This gives:

y = ab^x

1 = ab^0

b^0 \to 1

So:

1 = a*1

1 = a

a =1

Also: (x_5,y_5) = (4,16)

This gives:

y = ab^x

16 = 1 * b^4

16 = b^4

16 \to 2^4

So:

2^4 = b^4

Cancel the exponents (4)

2 =b

b = 2

So, the function y = ab^x is:

y = 2^x

<em>See attachment 2 for graph</em>

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3 years ago
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hope it helps luv

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