Assessing the perineum for bulging is a nursing priority to a client at the second labor stage. A bulging perineum is caused by the presence of the fetal head against the perineal area and usually signifies imminent birth. Pain medication is not administered this close to the birth instead it crosses the placenta barrier and can cause respiratory distress in the newborn. During this second stage of labor the client is encouraged to push, not pant, with each contraction.
Answer:
C. Cells in meiosis have unique genetic information
Explanation:
Meiosis is the cell division that forms four daughter cells from one parent cell. It includes two successive divisions called as meiosis I and meiosis II. Crossing over during prophase I of meiosis I imparts new gene combinations to the daughter cells of meiosis. Hence, daughter cells formed by the end of meiosis have some new gene combinations, that is, unique genetic information.
The frequency <em>p</em> of the yellow (A) allele is <em>p</em>= 0.3
The frequency <em>q</em> of the blue (a) allele is <em>q= </em><em>0.7</em>
Hardy–Weinberg equilibrium, states that allele and genotype frequencies in a population will remain constant from generation to generation. Equilibrium is reached in the absence of selection, mutation, genetic drift and other forces and allele frequencies p and q are constant between generations. In the simplest case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes.
p²+2*p*q+q²= 1 p+q= 1 q= 1-p
yellow (p²)= 9%= 0.09 p= √0.09= 0.3
green (2*p*q)= 42%= 0.42
blue (q²)=49%= 0.49 q=1-0.3= 0.7 <em>or</em> q= √0.49= 0.7
Answer : true
hope this helps
