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2 years ago

Han buys an item with a normal price of 15$ and uses a 10% off coupon. How much does he save by using the coupon

Mathematics

1 answer:

valina [46]2 years ago

6 0

Answer: $1.50

Step-by-step explanation:

The item's normal price is $15.

Han uses a 10% off coupon so he saves 10% which is:

= 15 * 10%

= $1.50

He therefore bought the item for $8.50.

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What is the mean of 23,25,24,26,23,25,22,22,23,40

TiliK225 [7]

To find the mean add all numbers than divide by quantity

all numbers added give = 253

mean = 253/ 10 = 25.3

mean = 25.3

:)

8 0

2 years ago

Read 2 more answers

Show that (4p^2-3q)^2+48p^2q =(4p^2+3q^2)

Brut [27]

Given:

The statement is

$(4p^2-3q)^2+48p^2q=(4p^2+3q^2)$

To prove:

The given statement.

Solution:

We have,

$(4p^2-3q)^2+48p^2q=(4p^2+3q^2)$

Now,

$LHS=(4p^2-3q)^2+48p^2q$

Using $(a-b)^2=a^2+b^2-2ab$ , we get

$LHS=(4p^2)^2+(3q)^2-2(4p^2)(3q)+48p^2q$

$LHS=(4p^2)^2+(3q)^2-24p^2q+48p^2q$

$LHS=(4p^2)^2+(3q)^2+24p^2q$

It can be rewritten as

$LHS=(4p^2)^2+(3q)^2+2(4p^2)(3q)$

Using $(a+b)^2=a^2+b^2+2ab$ , we get

$LHS=(4p^2+3q^2)$

$LHS=RHS$

Hence proved.

5 0

2 years ago

Mrs. Hanley shopping for school supplies for her children she picks up five folders and three notebooks for their classes and tw

Fiesta28 [93]

5 folders - $2 each = 10 $
3 note books - $3 each = 9 $
17 book covers minus 12 = 5
5 book covers - $1 each = 5$

10 + 9+5 = 24$

3 0

2 years ago

4# is a two digit number ,where # represents the digit at ones place . 7999 ÷ 4# lies between ---------

Hitman42 [59]

Answer:

$7999 \div 4\#$ lies between 163.245 and 199.975

Step-by-step explanation:

Given

2 digit = 4#

Required

The range of $7999 \div 4\#$

Let

$\# = 0$ --- the smallest possible value of #

So:

$7999 \div 40 = 199.975$

Let

$\# = 9$ --- the largest possible value of #

So:

$7999 \div 49 = 163.245$

<em>Hence, </em> $7999 \div 4\#$ <em> lies between 163.245 and 199.975</em>

4 0

2 years ago

In a state where license plates contain six digits, what is the probability that the license number of a randomly selected car h

andre [41]

Answer:

Step-by-step explanation:

Given : In a state where license plates contain six digits.

Probability of that a number is 9 = $\dfrac{1}{10}$ [Since total digits = 10]

We assume that each digit of the license number is randomly selected .

Since each digit in the license plate is independent from the other and there is only two possible outcomes for given case (either 9 or not), so we can use Binomial.

Binomial probability formula: $P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where n= total trials , p = probability for each success.

Let x be the number of 9s in the license plate number.

$X\sim Bin(n=6, p=\dfrac{1}{10}})$

Then, the probability that the license number of a randomly selected car has exactly two 9's will be :

$P(X=2)=^6C_2(\dfrac{1}{10})^2(1-\dfrac{1}{10})^{6-2}\\\\=\dfrac{6!}{2!(6-2)!}(\dfrac{1}{100})(\dfrac{9}{10})^4=0.098415$

Hence, the required probability = 0.098415

5 0

2 years ago