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Stolb23 [73]
3 years ago
7

A game involves tossing a biased coin that has a 60% probability of landing on heads. If a player wins $50 when heads appears, w

hat is the expected value of a player's winnings?
Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0
Probability of winning = 0.6 , Probability losing = 1-0.6 = 0.4

Expected value = 50(0.6) - 1(0.4)  =  $29.6

The interpreation of this is that if you play many times you would expect a profit of $29.6.
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anayas team won 5 out of every 7 games this season if the team played 28 games this season how many games did they win
OleMash [197]

Anaya’s Team won 20 games

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3 years ago
Suppose a mutual fund qualifies as having moderate risk if the standard deviation of its monthly rate of return is less than 5​%
Leokris [45]

Answer:

\chi^2 =\frac{28-1}{25} 21.7156 =23.453

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(23.453,27,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly lower than 5% so we can't conclude that we have a moderate risk for this case.

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=28 represent the sample size

\alpha=0.1 represent the confidence level  

s^2 =21.7156 represent the sample variance obtained

\sigma^2_0 =25 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 25, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 25

Alternative hypothesis: \sigma^2

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{28-1}{25} 21.7156 =23.453

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 27. And since is a right tailed test the p value would be given by:

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(23.453,27,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly lower than 5% so we can't conclude that we have a moderate risk for this case.

4 0
3 years ago
.875 written as a percentage
Alex17521 [72]

Answer:

87.5%

Step-by-step explanation:

to write a percentage as a number you move the decimal to the left 2 times.

7 0
3 years ago
Read 2 more answers
What is 15% of 76, rounded to two decimal places?
galben [10]

Answer: 11.4

Step-by-step explanation:

I did part / whole = % / 100

So x / 76 = 15 / 100

76 x 15 = 1140

1140 ÷ 100 = 11.4

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3 years ago
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CALC BC HELPPP!!!??? 100PTS!!!
lyudmila [28]

the assumption being that "x" is a plain variable whilst "y" is a function, that matters because the chain rule would be needed for a function, not so for a plain variable.

4x^2+4x+xy=5\implies 8x+4+\stackrel{\textit{product rule}}{\left( 1\cdot y+x\cdot \cfrac{dy}{dx} \right)}=0 \\\\\\ x\cfrac{dy}{dx}=-8x-4-y\implies \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x}

now, we know that y(5) = -23, which is another way of saying that when x = 5, y = -23, but we already knew that, we can get that by simply plugging it into the equation hmmm y'(5), well

\left. \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x} \right|_{\stackrel{x=5~}{\textit{\tiny y=-23}}}\implies \cfrac{-8(5)-4-(-23)}{5}\implies \cfrac{-21}{5}

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