2 years ago

What is the equation of the line that passes through (1,2) and is parallel to the line whose equation is 4x+y-1=0?

2 answers:

loris [4]2 years ago

8 0

Answer:It is very easy to work out, you just have to put them into slope-intercept form which is y=mx+b

Step-by-step explanation:

6 0

the answer would 4x+y+6=0

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Strike441 [17]

Step-by-step explanation:

=0.25x-12 I hope this helped:)

8 0

3 years ago

Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

$2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1$

Then factorizing the difference of squares, $x^2-1=(x-1)(x+1)$ , we end up with

$\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}$

3 0

2 years ago

FromTheMoon [43]

Sorry i just need points, hope you get ur answer

7 0

2 years ago

Softa [21]

2n-(n-7)=12
n+7=12
12-7=5
n=5

6 0

3 years ago

babymother [125]

Step-by-step explanation:

Range of relation ={-3,0,3,5}

8 0

3 years ago