Answer:
Step-by-step explanation:
Let x represent the seating capacity
Number of seats = 40+x
Profit per seat = 10 - 0.20x
For maximum number of seats
P(x) = ( 40+x ) ( 10-0.20x )
P(x) = 400+10x-8x-0.2x^2
P(x) = 400+2x- 0.2x^2
Differentiating with respect to ( x )
= 2 - 0.4x
0.4x = 2
x = 2/0.4
x = 5
The seating capacity will be 40+5 = 45
For the maximum profits
40X10+ 9.9 + 9.8 + 9.7 + 9.6 + 9.5 + 9.4 + 9.3 + 9.2 + 9.1 + ... 1.0, 0.9, 0.8, 0.6, 0.5, 0.4, 0.3, 0.2, 0.1
= 400 + an arithmetic series (first term = 0.1, common difference = 0.1, number of terms = 8+ 40 = 48 )
= 400 + (48/2)(2X0.1 + (48-1)X0.1)
= 400 + 24(0.2 + 4.7)
= 400 + 24(4.9)
= 400 + 117.6
= 517.6
= 517.6dollars
Answer:
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Step-by-step explanation:
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