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bekas [8.4K]
3 years ago
10

HELP GEOMETRY PLEASE

Mathematics
1 answer:
Alexandra [31]3 years ago
4 0
For each of the problems, twice the angle formed by the chords is equal to half the sum of the angles of the arcs.

So, for the first problem, we have 94 \cdot 2 = x+103, so x = 188 - 103 = 85. 

For the second, 102 \cdot 2 = x + 118, so x = 204 - 118 = 86.

For the last problem, 106 \cdot 2 = x + 88, so x = 212 - 88 = 124.

Feel free to comment below if you have any questions!
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Which expression is equivalent to √4j^4/9k^8?
solmaris [256]
\frac{ 2j^{2} }{ 3^{4} }
SQRT each individual bit: 4 andj^{4} and 9 and k^{8}
6 0
3 years ago
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Find the length of a missing side, x , in the triangle at right. Show the work leading to your answer
BARSIC [14]

Answer:

48

Step-by-step explanation:

!3x5 is 48

5 0
2 years ago
????????????????????????????? can someone do this thanks
shusha [124]

Answer:

ima say 32 bc i used a calculator

Step-by-step explanation:

5 0
3 years ago
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Suppose a 95% confidence interval for μ turns out to be (1,000, 2,100). give a definition of what it means to be "95% confident"
IRISSAK [1]

Answer:

In repeated sampling, 95% of the intervals constructed would contain the population mean.

3 0
3 years ago
In triangle abc, the perimeter is 36, and ab=ac. line ad is perpendicular to bc at the point d, and triangle abd's perimeter is
Musya8 [376]
Let x=ab=ac, and y=bc, and z=ad.

Since the perimeter of the triangle abc is 36, you have:

Perimeter of abc = 36
ab + ac + bc = 36
x + x + y = 36
(eq. 1) 2x + y = 36

The triangle is isosceles (it has two sides with equal length: ab and ac). The line perpendicular to the third side (bc) from the opposite vertex (a), divides that third side into two equal halves: the point d is the middle point of bc. This is a property of isosceles triangles, which is easily shown by similarity.

Hence, we have that bd = dc = bc/2 = y/2 (remember we called bc = y).

The perimeter of the triangle abd is 30:

Permiter of abd = 30
ab + bd + ad = 30
x + y/2 + z =30
(eq. 2) 2x + y + 2z = 60

So, we have two equations on x, y and z:

(eq.1) 2x + y = 36
(eq.2) 2x + y + 2z = 60

Substitute 2x + y by 36 from (eq.1) in (eq.2):

(eq.2') 36 + 2z = 60

And solve for z:

36 + 2z = 60 => 2z = 60 - 36 => 2z = 24 => z = 12

The measure of ad is 12.

If you prefer a less algebraic reasoning:

- The perimeter of abd is half the perimeter of abc plus the length of ad (since you have "cut" the triangle abc in two halves to obtain the triangle abd).

- Then, ad is the difference between the perimeter of abd and half the perimeter of abc:

ad = 30 - (36/2) = 30 - 18 = 12
4 0
3 years ago
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