All categories

3 years ago

What is the remainder when (2x3 + x2 – 3x + 4) is divided by x – 2?

Mathematics

1 answer:

sergeinik [125]3 years ago

8 0

Answer:

The remainder is

−

Step-by-step explanation:

When

P ( x ) = 2 x 3 – x 2 – 3 x + 7 is divided by x + 2 ,we are dividing by x −( − 2), so the remainder will be: P ( − 2 ) = 2 − 2 ) 3 –

(

−

)

–

(

−

)

−

You might be interested in

Mayroong 10 abokado sa bawat basket.kung mayroong 8 basket,ilan lahat ang abokado?

trapecia [35]

Waaaaaaaaaaaat????????

5 0

2 years ago

Line l is the perpendicular bisector of AB. What is the perimeter of ABC

saveliy_v [14]

Answer:

Perimeter = 60

Step-by-step explanation:

because l bisects AB:

3y+1 = 5y-5

reduce:

2y = 6

y = 3

and:

2x+4 = 4x-12

reduce:

2x = 16

x = 8

AB = (3y+1) + (5y-5)

AB = 8y-4

substitute for y

AB = 8(3)-4

AB = 20

Perimeter = (2x+4) + (4x-12) + 20

reduce:

perimeter = 6x+12

substitute for x:

Perimeter =6(8)+12

reduce:

Perimeter = 60

3 0

2 years ago

A store is offering 40% off regular priced items. The amount of discount on an item is $6, What is the regular price of this ite

mote1985 [20]

The answer would be $15

All you need to do is multiply each one by .4 and see which one equals 6.

15 x .4 =6

Hope this helps!

6 0

2 years ago

Read 2 more answers

If Joseph buys a T.V. At 35% off and it’s original costs $599.99 how much did he pay for the tv?

Monica [59]

Answer: He paid $\$389.9935$ for the T.V.

Step-by-step explanation:

We need to analize the information provided:

- The original cost of the T.V. was $599.99

- Joseph buys it at 35% off the original cost.

Let be "x" the amount Joseph paid for the T.V.

We can calculate "x" with the following expression:

$x=\$599.99-(\$599.99)(0.35)\\\\x=\$389.9935$

Therefore, he paid $\$389.9935$ for the T.V.

7 0

3 years ago

The lengths of the diagonals of a rhombus are 2x and 10x. What expression gives the perimeter of the rhombus?

True [87]

Answer:

$P=4x\sqrt{26}\ units$

Step-by-step explanation:

we know that

The sides of a rhombus are all congruent and the diagonals are perpendicular bisectors of each other

Applying the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the length side of the rhombus

a and b are the semi-diagonals

we have

$a=2x/2=x\ units\\b=10x/2=5x\ units$

substitute the values

$c^2=x^2+(5x)^2$

$c^2=26x^2$

$c=x\sqrt{26}\ units$

To find out the perimeter of the rhombus multiply the length side by 4

$P=(4)(x\sqrt{26})$

$P=4x\sqrt{26}\ units$

6 0

3 years ago