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2 years ago

7

Christian earned $475 from mowing lawns last summer. He deposited this money in an account that pays an interest rate of 3.8% co

mpounded annually. What will be his balance after 15 years?

1 answer:

kvasek [131]2 years ago

6 0

475 * (1.038)^15 = 831.10120562 = $831.10

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10(4-3i)= whats the answer

LenaWriter [7]

Answer: Hi!

To solve this equation, we first distribute to the terms inside of the parentheses.

10*4 = 40

10*-3i = -30i

Our equation now looks like this:

40 - 30i

There is nothing left to simplify, so you're done!

Hope this helps!

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2 years ago

Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.

Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

$\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0$

$\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill$

3 0

3 years ago

James wants to promote his band on the internet. Site A offers website hosting for $4.95 per month with a $49.95 startup fee. Si

cupoosta [38]

Answer:

Part 1) see the procedure

Part 2) $4.95x+49.95 < 9.95 x$

Part 3) $x > 9.99\ months$

Part 4) The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months

Step-by-step explanation:

Part 1) Define a variable for the situation.

Let

x ------> the number of months

y ----> the total cost monthly for website hosting

Part 2) Write an inequality that represents the situation.

we know that

Site A

$y=4.95x+49.95$

Site B

$y=9.95x$

The inequality that represent this situation is

$4.95x+49.95 < 9.95 x$

Part 3) Solve the inequality to find out how many months he needs to keep the website for Site A to be less expensive than Site B

$4.95x+49.95 < 9.95 x$

Subtract 4.95x both sides

$4.95x+49.95-4.95x < 9.95 x-4.95x$

$49.95 < 5x$

Divide by 5 both sides

$49.95/5 < 5x/5$

$9.99 < x$

Rewrite

$x > 9.99\ months$

Part 4) describe how many months he needs to keep the website for Site A to be less expensive than Site B.

The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months

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3 years ago

Question 4 of 10

nadezda [96]

Answer:

<A=<D

Step-by-step explanation:

I just took the quiz

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2 years ago

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worty [1.4K]

Answer:

lol

Step-by-step explanation:

im not even sure try using google

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2 years ago