0.25q + 0.10d = 1.25
q + d = 8....q = 8 - d
0.25(8 - d) + 0.10d = 1.25
2 - 0.25d + 0.10d = 1.25
-0.25d + 0.10d = 1.25 - 2
-0.15d = - 0.75
d = -0.75/-0.15
d = 5 <=== there are 5 dimes
q + d = 8
q + 5 = 8
q = 8 - 5
q = 3 <=== there are 3 quarters
You need to factor the radicals into products of radicals, and when factoring you should keep in mind you want to obtain perfect square roots. So √125 = √5*√25 and squareroot 25 has a definite answer of 5, so ∛125=∛5×∛25=5×√5. You want to follow the general pattern of factoring perfect squares to obtain a number outside the radical which can be multiplied by the current coefficient
Answer:
4
Step-by-step explanation:
7x = x² - 8
=> x² - 7x - 8 = 0
use quadratic formula:
a = 1, b = -7, c = -8
x = 
<em>(pls ignore the "A" I don't know why it's showing up)</em>
=> x = 
=> x = 
=> x = 
= 4 or 
= -5 <em>(the answer is only 4 since it's asking for the positive solution)</em>
Answer:
92
Step-by-step explanation:
HSKDBEJJDBDISHDHIS
