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maria [59]
4 years ago
7

The area of a triangular block is 64 square inches. If the base of the triangle is twice the height, how long are the base and t

he height of the triangle? Will award brainliest!!!

Mathematics
1 answer:
jek_recluse [69]4 years ago
8 0
Algebra problem really.

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Y=-4x+6<br> Find an equation for the inverse relation
kherson [118]

Answer:

Step-by-step explanation:

y = -4x + 6.....switch x and y and solve for y

x = -4y + 6 ....subtract 6 from both sides

x - 6 = -4y....divide by -4 on both sides

(x - 6) / -4 = y or y = -1/4x + 3/2 <====

3 0
3 years ago
ishmal invested £3500 for 3 years at 2.5% per annum simple interest. Work out the total amount of interest Ishmal earned.
Jlenok [28]

Answer:

Interest Earned is $262.5

Step-by-step explanation:

Interest=PRT/100

When P=Principal, R=Rate, T=Time

Interest earn =( 3500 x 3 x 2.5)/ 100

I=$26,250 / 100

I=$262.5

6 0
4 years ago
SURFACE AREAS - PYRAMIDS?
Bond [772]

The total surface area consists of the base area and the surface area (the area of all lateral faces). The base is a hexagon with side a=3 cm.

A_{hexagon}=6A_{triangle}=6\cdot \dfrac{1}{2} \cdot \dfrac{a^2\sqrt{3}}{4} =\dfrac{3}{4} \cdot 3^2\cdot \sqrt{3}=\dfrac{27\sqrt{3}}{4} sq. cm.

Each lateral face is an isosceles triangle with height h=12 cm and base a=3 cm. The area of one such lateral triangle is

A_{lateral}=\dfrac{1}{2}\cdot h\cdot a= \dfrac{1}{2}\cdot 12\cdot 3=18 sq. cm.

Then the total surface area is:

A_{total}= \dfrac{27\sqrt{3}}{4} +6\cdot 18=\dfrac{27\sqrt{3}}{4} +108=11.7+108=119.7 sq. cm.

Answer: 119.7 sq. cm.

7 0
4 years ago
6 radians is the same as ____°.<br> Round to the nearest hundredth of a degree.
sladkih [1.3K]

Answer:

343.77°

Step-by-step explanation:

1 radian =  \frac{180}{Pi}°

6 radians will be;

6 ×  \frac{180}{Pi}° =343.7746771 °

Or 343.77° (rounded up to nearest hundredth)

6 0
4 years ago
Read 2 more answers
Solve for x.<br><br>79=<img src="https://tex.z-dn.net/?f=%2027%5E%7Bx%7D%20" id="TexFormula1" title=" 27^{x} " alt=" 27^{x} " al
tatiyna
79=27^x\\&#10;x=\log_{27}79
7 0
4 years ago
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