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3 years ago

7

The area of a triangular block is 64 square inches. If the base of the triangle is twice the height, how long are the base and t

he height of the triangle? Will award brainliest!!!

1 answer:

jek_recluse [69]3 years ago

8 0

Algebra problem really.

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What is the measure of the vertex angle of an isosceles

pshichka [43]

Answer:

A) 96

Step-by-step explanation:

The 2 base angles are both 42* thus adding up to 84*. 180-84=96

You are welcome.

3 0

3 years ago

Three married couples go to a movie theater. if they sit together in a row of 6 empty seats, find the probability that each woma

Ganezh [65]

Given are three married couples.

So, let us assume there are 3 men and 3 women

They are sitting in a row of 6 empty seats

There is a definite order constraint that each woman will sit left to her husband. The first woman gets 3 options to choose from 3 available seats. The second woman has two options left as already one seat is filled by the first woman. The last woman has one option left. So, it is $3*2*1$

So, number of ways is 3! = $3*2*1$ = 6 ways.

5 0

3 years ago

From a radar station, the angle of elevation of an approaching airplane is 32.5 degree. The horizontal distance between the plan

denis23 [38]

Answer: 42.21 km

Step-by-step explanation:

We can solve this using trigonometry, since we have the following data:

$\theta=32.5\°$ is the the angle of elevation

$d=35.6 km$ is the horizontal distance between the plane and the radar station

$x$ is the hypotenuse of the right triangle formed between the radar station and the airplane

Now, the trigonometric function that will be used is <u>cosine</u>:

$cos\theta=\frac{d}{x}$ because $d$ is the adjacent side of the right triangle

$cos(32.5\°)=\frac{35.6 km}{x}$

Finding $x$ :

$x=\frac{35.6 km}{cos(32.5\°)}$

$x=42.21 km$

4 0

3 years ago

What % of 300 is 30

algol13

Answer:10%

Step-by-step explanation:

5 0

3 years ago

Factor the polynomial F(x) =x^3-x^2-4x+4 completely.

Norma-Jean [14]

Answer:

Step-by-step explanation:

PART 1:

Possible roots by noticing the coefficient of first term:

x = 1, -1

PART 2:

1 | 1 -1 -4 4

<u> 1 0 -4</u>

1 0 -4 0

The remainder is zero, hence one factor is (x-1)

PART 3:

$x^3-x^2-4x+4=(x^2-4)(x-1)\\\\x^3-x^2-4x+4=(x+2)(x-2)(x-1)$

PART 4:

$f(x)=(x+2)(x-2)(x-1)\\\\=(x^2-4)(x-1)\\\\=x^3-4x-x^2+4\\\\=x^3-x^2-4x+4$

6 0

2 years ago