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never [62]
3 years ago
7

What is the x-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:5?

Mathematics
2 answers:
mixer [17]3 years ago
4 0

The given end points of the line of the given graph are J(-6,-2) and K( 8,-9).

We need to find the coordinate of x that divide the line segment from J to K in 2:5 ratio.

We are given formula also.

x=\left(\frac{m}{m+n}\right)\left(x_2-x_1\right)+x_1

We have m = 2, n= 5, x1 = -6 and x2 = 8.

Plugging those values of m, n, x1 and x2 in above formula, we get

x=\left(\frac{2}{2+5}\right)\left(8-\left(-6\right)\right)+\left(-6\right)

=\frac{2}{7}\left(8+6\right)-6

=\frac{2\cdot \:14}{7}-6

=4-6

x=-2

<h3>Therefore, correct option is 2nd option -2.</h3>
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

it is -2 oprion 2

Step-by-step explanation:

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3 years ago
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3 0
3 years ago
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3. Which point lies inside the circle with equation (x - 2)2 + (y + 3)2 = 4?
timofeeve [1]

Answer:

C (2,-4)

Step-by-step explanation:

You could graph the circle and then graph the points and see...

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So if you wanted to draw it is a circle with center (2,-3) and radius 2.

If you want to do it the other way:

Plug in time!

(2,-5)?

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(2,-4)?

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