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never [62]
3 years ago
7

What is the x-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:5?

Mathematics
2 answers:
mixer [17]3 years ago
4 0

The given end points of the line of the given graph are J(-6,-2) and K( 8,-9).

We need to find the coordinate of x that divide the line segment from J to K in 2:5 ratio.

We are given formula also.

x=\left(\frac{m}{m+n}\right)\left(x_2-x_1\right)+x_1

We have m = 2, n= 5, x1 = -6 and x2 = 8.

Plugging those values of m, n, x1 and x2 in above formula, we get

x=\left(\frac{2}{2+5}\right)\left(8-\left(-6\right)\right)+\left(-6\right)

=\frac{2}{7}\left(8+6\right)-6

=\frac{2\cdot \:14}{7}-6

=4-6

x=-2

<h3>Therefore, correct option is 2nd option -2.</h3>
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

it is -2 oprion 2

Step-by-step explanation:

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Answer:

n = 78

Step-by-step explanation:

IQR is the interquartile range of the data set.

So Saul had already arranged the data in order, that is the first step when calculating the interquartile range.

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Next, is to find the median so we could easily separate the data into quartiles.

The median of the data 25, 30, 50, 50, 50, 50, 56, n., 250 = 50

Then, arrange the data into the first quartile and the third quartile

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Since 27 is the interquartile range, n=

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54 = (56 + n) - 80

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