Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
Answer:
(p • 10) - (p • 2)
Step-by-step explanation:
To be doubly sure of your answer, do the actual mult.:
p(10-2) = 10p - 2p. This is equivalent to (p • 10) - (p • 2) (Answer D).
Answer:
?=19
x=30
Step-by-step explanation:
5/6x - 1/5x = 19
5(5/6x) - 6(1/5x) = 19
25/30x-6/30x=19
19/30x=19
19x=19(30)
19x=570
x= 570/19
x=30