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ryzh [129]
3 years ago
9

One dozen students each drop a brass tack six times from a height of six inches onto a level hard surface. They record the numbe

r of times the tack lands point up. The table below lists their results.
What was the experimental probability that the tack lands point-up for student 4?

Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Experimental Probability = 2/3

To find the experimental probability that the tack lands point-up for student 4, we can use the following equation

\frac{Point-up}{Attempts}\\\frac{4}{6} or\frac{2}{3}

If this helped you a Brainliest would be appreciated!

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The ordered pair below is a solution to which equation 36,4
viktelen [127]

Heyyyyyyy

9 is to 1

Hope it helps

8 0
3 years ago
I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

3 0
3 years ago
paul , Nadia and Jim have some stickers. Nadia has 3 times as many stickers as jim. Paul has 25 stickers more that Nadia. Paul a
alexandr402 [8]
Nadia = 3x than Jim
Paul = 25+ than Nadia
Jim = ?
Nadia and Paul = 85

85-25 = 60
(Subtract Nadia's and Paul's stickers all together with the stickers that Paul have more so both of the stickers are balance)

Nadia = 60/2 =30
Paul = 30+25 =55

Jim= 30/3=10

#Jim have 10 stickers


4 0
3 years ago
Q is equidistant from the sides of ZTSR. Find mZRST. The
melisa1 [442]

9514 1404 393

Answer:

  40°

Step-by-step explanation:

Triangles QRS and QTS are congruent (HL), so the marked angles are also congruent:

  3x +2 = 4x -4

  6 = x

Then the total angle measure of angle RST is ...

  (3x +2) +(4x -4) = 7x -2 = 7(6) -2 = 40 . . . degrees

m∠RST = 40°

6 0
3 years ago
Will give brainliest
posledela

Answer:

8

Step-by-step explanation:

hope it will help good luck

7 0
3 years ago
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