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2 years ago

Identify a and b for the hyperbola with equation

Mathematics

1 answer:

Nady [450]2 years ago

7 0

Answer:

identify a and b for the hyperbola with equation

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Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5 x minus 8 when x is less than 0

mariarad [96]

Find Lim f(x) as x->0

for

f(x)=5x-8 ......x<0

f(x)=|-4-x|......x ≥ 0

Clearly

f(0)=|-4-0|=|-4|=4 exists.

The left-hand limit, as x-> 0- is f(0-)=5(0)-8=-8

The right hand limit, as x->0+ is f(0+)=|-4-0|=|-4|=4

Since the left and right limits do not both equal f(0), the limit does not exist.

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2 years ago

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What are the roots of this quartaic equation?<br> -102 + 12r - 9 = 0

elena-14-01-66 [18.8K]

Answer:

$r = \frac{37}{4}$

I hope this helps!

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2 years ago

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a farmer is buying fencing to surround a square field of area 3600m^2. What length of fencing does he need to buy?

kirill115 [55]

Answer:

240 m

Step-by-step explanation:

The area of a square field is 3600 m².

We need to find the length of fencing he needs to buy. It means we need to find the perimeter of the field.

The area of a square field is given by :

A = side²

So,

$s=\sqrt{3600} \ m\\\\s=60\ m$

Length of fencing = perimeter

= 4(s)

= 4(60)

= 240 m

So, he would need to buy 240 m of fencing.

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2 years ago

A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.

yawa3891 [41]

Answer:

The probability is 0.003

Step-by-step explanation:

We know that the average $\mu$ is:

$\mu=500$

The standard deviation $\sigma$ is:

$\sigma=100$

The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

We seek to find

$P(x800)$

For P(x>800) The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

$Z=\frac{800-500}{100}$

$Z=3$

The score of Z = 3 means that 800 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

$P(x>800)=0.15\%$

For P(x<200) The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

$Z=\frac{200-500}{100}$

$Z=-3$

The score of Z = -3 means that 200 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

$P(x$

Therefore

$P(x800)=P(x800)$

$P(x800)=0.0015 + 0.0015$

$P(x800)=0.003$

6 0

2 years ago

For a science experiment Marcia dissolved 1.0 kilogram of salt in 3.0 liters of water. For a different experiment, Bobby dissolv

nekit [7.7K]

Marcia dissolved 1 kg of salt in 3 litres of water.
Bobby dissolves 2 pounds of salt in 7 pints of water
2.11 pints = 1 litre
7 pints = 7/2.11
= 3.32 litre
1 pound =0.45 kg
2 pound = o.45*2 kg
= 0.9 kg
So we find that Bobby is dissolving 0.9kg of salt in 3.32 litre of water
Marcia is dissolving 1 kg of salt in 3 litres of water.

5 0

2 years ago