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pashok25 [27]
3 years ago
11

About​ ______% of the area is between z= -1 and z= 1 ​(or within 1 standard deviation of the​ mean)? How do you solve this?

Mathematics
1 answer:
nexus9112 [7]3 years ago
8 0

Answer:

68%

Step-by-step explanation:

<em><u>68-95-99.7% Rule:</u></em>

<em><u /></em>

This is the empirical rule which is used to remember the percentage of values that is within a band of the mean. We say:

  • 68% of the data fall within 1 standard deviation of the mean
  • 95% of the data fall within 2 standard deviation of the mean, and
  • 99.7% of data falls within 3 standard deviations of the mean

Clearly, from the empirical rule, we see that about 68% of the area is between z = -1 and z = 1 (or within 1 standard deviation of the mean)

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Y = 2/3 x -3 y = -3/2 x +2 what statement about the lines are true
Hoochie [10]

Answer:

The product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

Thus, the lines are perpendicular.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the lines

y = 2/3 x -3       --- Line 1

y = -3/2x +2      --- Line 2

<u>The slope of line 1</u>

y = 2/3 x -3       --- Line 1

By comparing with the slope-intercept form of the line equation

The slope of line 1 is: m₁ = 2/3

<u>The slope of line 2</u>

y = -3/2x +2      --- Line 2

By comparing with the slope-intercept y = mx+b form of the line equation

The slope of line 2 is: m₂ = -3/2

We know that when two lines are perpendicular, the product of their slopes is -1.

Let us check the product of two slopes m₁ and m₂

m₁ × m₂ = (2/3)(-3/2 )

m₁ × m₂ = -1

Thus, the product of the slopes of lines is -1.

i.e. m₁ × m₂ = -1

Thus, the lines are perpendicular.

7 0
3 years ago
Find the volume of the shaded figure by subtracting the smaller volume from the larger
alekssr [168]

Answer:

a. 9a^3 - 9ab^2

b. 9a(a^2 - b^2)

Step-by-step explanation:

a.

Volume = l*w*h

Volume_{smaller} = l*w*h

Where, l = 9a, w = b, h = b

Volume_{smaller} = 9a*b*b = 9ab^2

Volume_{larger} = l*w*h

Where, l = 9a, w = a, h = a

Volume_{smaller} = 9a*a*a = 9a^3

Volume of the shaded figure = 9a^3 - 9ab^2

b. 9a^3 - 9ab^2 expressed in factored form:

Look for the term that is common to 9a³ and 9ab², then take outside the parenthesis.

9a^3 - 9ab^2 = 9a(a^2 - b^2)

6 0
4 years ago
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Answer:

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