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zhannawk [14.2K]
2 years ago
9

Plz help me plz f(87) = -590.6 and f(132) = -901.1

Mathematics
1 answer:
quester [9]2 years ago
4 0

Answer:

  ididk

Step-by-step explanation:

  ddkkdk

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Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre
choli [55]

Answer:

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

\hat p=\frac{46}{115}=0.4 estimated proportion of people that have traded in their old car

p_o=0.48 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:  

Null hypothesis:p\geq 0.48  

Alternative hypothesis:p < 0.48  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

4 0
3 years ago
1. 2,000(x -0.03) = 6,000
Tasya [4]
1. x=3.03
2.x=0.5
3.x=4/3
4.x=2
5.x=10
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3 years ago
Point B is on line segment \overline{AC}
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I really can’t help you but I’ll wish look for you
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What methods of charging does John use?
lidiya [134]

Answer: The rod through induction electroscope through friction

Step-by-step explanation:

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This is the result of solving an equation to find a value(s) for the variable(s) which make the equation true.
SOVA2 [1]

Answer:

Step 1: Simplify both sides of the equation.

8−2(3−x)=4x+6

8+(−2)(3)+(−2)(−x)=4x+6(Distribute)

8+−6+2x=4x+6

(2x)+(8+−6)=4x+6(Combine Like Terms)

2x+2=4x+6

2x+2=4x+6

Step 2: Subtract 4x from both sides.

2x+2−4x=4x+6−4x

−2x+2=6

Step 3: Subtract 2 from both sides.

−2x+2−2=6−2

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Step 4: Divide both sides by -2.

−2x

−2

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Step-by-step explanation:

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