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Zarrin [17]
2 years ago
5

ΔA'B'C' is the image of a reflection of ΔABC across the line x=1. The y-coordinates of the vertices of ΔABC and its image ΔA'B'C

' are

Mathematics
1 answer:
seropon [69]2 years ago
4 0

Answer:

A(y=3) B(y = -2) C(y= 4)

A' (y = 3) B(y= -2) C(y= 4)

Step-by-step explanation:

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Answer:

Simplify the expression: (16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}

Use the exponent power:

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  • \sqrt[n]{a^n} =a
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(16y^{\frac{5}{4}}y^3)^{\frac{1}{2}}

Apply the given rules;

(16y^{\frac{5}{4} +3} )^{\frac{1}{2}}

Simplify:

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then;

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Therefore, the simplified expression of (16y^{\frac{5}{4}}y^3)^{\frac{1}{2}} is, 4y^{\frac{17}{8}}


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