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Zarrin [17]
2 years ago
5

ΔA'B'C' is the image of a reflection of ΔABC across the line x=1. The y-coordinates of the vertices of ΔABC and its image ΔA'B'C

' are

Mathematics
1 answer:
seropon [69]2 years ago
4 0

Answer:

A(y=3) B(y = -2) C(y= 4)

A' (y = 3) B(y= -2) C(y= 4)

Step-by-step explanation:

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ExtremeBDS [4]
F(x) = 3x² + 6x - 1

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x = -b/2a → x = -6/(2.3) = -1. Then the axis of symmetry is x = - 1
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Ten the vertex (minimum) is at (-1,- 4)


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