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solmaris [256]
2 years ago
12

Micheal used addition to find 9x100 and he said the product was 90. What did he do wrong?

Mathematics
1 answer:
Vlada [557]2 years ago
8 0

Answer:

He did 9 times 10 instead of 9 times 100.

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A business rents bicycles and in-line skates. Bike rentals cost $25 a day and skates cost $20 a day. The business had 20 rentals
Lena [83]
25x+20y=455
x+y=20


20x+20y=400
-25x-20y=-455
-5x=-55
x=11
11+y=20
y=9

Solved it as well, sorry if I wasn't supposed to

6 0
3 years ago
The table below represents different radios of a teaspoon of sugar to ounces of<br> Ice tea
daser333 [38]

Step-by-step explanation:

How are we supposed to answer theres no table

<3

6 0
2 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
The graph of f(x) = –3(x – 1)2 + 4 is shown on the left. Which interval defines the domain of the function? (-∞, 4) (-∞, 4] (-∞,
noname [10]

Answer:

C

Step-by-step explanation:

The graph can take any value of X

-3[ x^2 - 2x + 1] + 4

-3x^2 +6x -3 + 4

-3x^2 + 6x + 1

x can take any value of real numbers and there would be a solution

Hence all real numbers is the domain.

6 0
3 years ago
How many terms are there in this expression? 3a + b - 4c <br> ——-<br> 3<br> 6<br> 5
Dafna1 [17]

There's 3 terms

3a-----1

+b -----2

-4c------3

3 0
3 years ago
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