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2 years ago

12

Micheal used addition to find 9x100 and he said the product was 90. What did he do wrong?

1 answer:

Vlada [557]2 years ago

8 0

Answer:

He did 9 times 10 instead of 9 times 100.

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On the day that a certain celebrity proposes marriage, 252525 people know about it. Each day afterward, the number of people who

Serhud [2]

Answer:

A

Step-by-step explanation:

The graphs are attached.

First of all, the day proposal goes out, 25 people know, so the initial condition is y = 25 at x = 0.

Hence, graph would start at y = 25.

Looking at the graphs, we can eliminate B and D immediately because they start at 50.

Now, it says every day, this number (y) triples, so 1 day after, it would be:

25 * 3 = 75

So, the graph would show x = 1 and y = 75

We can eliminate "C" as it doesn't show 75 at x = 1.

And we look at A and it is correct.

So,

A is the graph of the situation represented.

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2 years ago

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Select the correct answer.

ki77a [65]

Answer:

d 68

Step-by-step explanation:

do not know hope it maybe might help you sorry wish i could help

7 0

3 years ago

Is -1.5 greater or less than 1.3

Katarina [22]

-1.5 is less than 1.3

4 0

2 years ago

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Can you help me with my math questions

GrogVix [38]

$p^2+2(7)p+7^2=(p+7)^2$

Justification:

Given: $p^2+14p+49$

Split the middle term;

$=p^2+7p+7p+49$

Factor:

$=p(p+7)+7(p+7)$

$=(p+7)(p+7)$

$=(p+7)^2$

QUESTION 3a

The given expression for the area of the rectangle is $36x^2-12x+1$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$36x^2-12x+1=289$

$\Rightarrow (6x-1)^2=289$

$\Rightarrow (6x-1)(6x-1)=289$

$\Rightarrow l=(6x-1),w=(6x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow (6x-1)=\pm \sqrt{289}$

$\Rightarrow (6x-1)=\pm 17$

$\Rightarrow 6x=1\pm 17$

$\Rightarrow 6x=18 \:or\:6x=-16$

$\Rightarrow x=3 \:or\:x=-\frac{2}{3}$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17$

QUESTION 3b

The given expression for the area of the rectangle is $25x^2-50x+25$ .

This is equal to the indicated area which is $1225\;in^2$

This implies that

$25x^2-50x+25=1225$

$25(x^2-2x+1)=1225$

$(5(x-1))^2=35^2$

$5(x-1)5(x-1)=49$

$\Rightarrow l=5(x-1),w=5(x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow 5(x-1)=\pm \sqrt{1225}$

$\Rightarrow 5(x-1)=\pm 35$

$\Rightarrow x=1\pm 7$

$\Rightarrow x=8 \:or\:x=-6$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=5(8-1)=35,w=5(8-1)=35$

QUESTION 3c

The given expression for the area of the rectangle is $49x^2-56x+16$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$49x^2-56x+16=289$

$(7x-4)^2=289$

$(7x-4)(7x-4)=289$

$\Rightarrow l=(7x-4),w=(7x-4)$

Applying the laws of indices gives;

$(7x-4)^2=17^2$

This implies that;

$7x-4=17$

$7x=21$

$x=3in.$

The side length of this rectangle is

$\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.$

Dont forget that the square is also a rectangle.

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2 years ago

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Layla borrowed some money from her friend in order to help buy a new video game

astra-53 [7]

Answer:

hi hru can you be my friend

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1 year ago