Answer:
4 ways of choosing
Step-by-step explanation:
If you want to choose 3 objects, without replacement, from the 4 objects which are distinct, then permutation i.e then their arrangement doesn't really matter. Only their combination will be considered
That means, order of choosing doesn't matter,
pencil/ eraser/ desk will be same as eraser/ desk/ pencil.
Number of ways of selecting 3 objects out of 4 distinct objects is:
⁴C₃ = 
⁴C₃ = 
⁴C₃ = 4
So, there are 4 ways of choosing
You can basically plug in the numbers for x and y into the options:
A. y/x = 3
12/4 = 3, so this one is right
B. xy = 3
12*4 = 48, so this is wrong
C. x = 3y
3*12 = 36, which is not x (4), so this is wrong
D. y = 3x
3*4 = 12, which is y (12), so this is right
So, A and D are right
Hey! How are you? My name is Maria, 19 years old. Yesterday broke up with a guy, looking for casual sex.
Write me here and I will give you my phone number - *pofsex.com*
My nickname - Lovely
Y = 1/3 x - 10 . . . (1)
2x + y = 4 . . . . . . (2)
Putting (1) into (2) gives, 2x + 1/3 x - 10 = 4
7/3 x - 10 = 4
7/3 x = 4 + 10 = 14
x = (3 x 14)/7 = 6
From (1), y = 1/3(6) - 10 = 2 - 10 = -8
x = 6, y = -8
