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2 years ago

An ice cream factory makes 330 quarts of ice cream in 5 hours. How many quarts could be made in 12 hours?

1 answer:

3 0

First find how many quarts are made per hour.

To do this, divide 330 quarts by 5 hours:
$330 \div 5$
This gives you 66 quarts per hour.

Multiply this by 12 to find out how much is made in 12 hours.
$66 \times 12$
Answer: 792 quarts

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which equation below represents the data in the table and PLEEEEASE show each and every step of how to solve I will make you the

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The equation which represents the data in the table as in the task content is; Choice C; y = 2x +3.

<h3>What is the equation which represents the data in the table as attached?</h3>

It follows from the task content that the slope of the relation can be determined by means of the slope formula for a linear equation as follows;

Slope = (1-(-1))/(-1 -(-2))

Slope = 2.

Hence, the equation which represents the function is;

2 = (y-(-1))/(x -(-2))

2x + 4 = y +1

y = 2x + 3.

Therefore, the equation which represents the data in the table as in the task content is; Choice C; y = 2x +3.

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Write a linear function f either the values f (-1)=5 and f (3)=4

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$f(x) = - \frac{1}{4}x + \frac{19}{4} \\$

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2 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

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3 years ago