Substitute the given values for the parameters in the point-slope form of the equation of a line. That form is
y - k = m(x - h)
for point (h, k) and slope m.
You have (h, k) = (1, 2) and m=-3, so your equation is
y - 2 = -3(x - 1)
The difference between them is 43. :) Hope this helped!
Solution:x^2+3x-4=(x+4)(x-1)>0,
therefore, the x range is (-∞,-4)∪(1,+∞).
Answer:(-∞,-4)∪(1,+∞).[
Answer:
For the triangle having the sides 122m, 120m and 22m :
s=
2
122+120+22
=132m
Area of triangle =
s(s−a)(s−b)(s−c)
=
132(132−122)(132−120)(132−22)
=
132×10×12×110
=1320m
2
For the triangle having the sides 22m, 24m and 26m :
s=
2
22+24+26
=36m
=
36(36−22)(36−24)(36−26)
=
36×14×12×10
=24
105
=24×10.25m
2
(approx.)=246m
2
There, the area of the shaded portion
=(1320−246)m
2
=1074 m
2
