What pattern do you see 5, 10, 15, 20, 25 and 8, 16, 24, 32 and 40

Mathematics

2 answers:

Bas_tet [7]3 years ago

6 0

For the 1st pattern is adding 5 to each number. for 2nd pattern it is adding 8 to each number.

Maslowich3 years ago

3 0

For one +5, for another +8

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Ray delivered 3/8 of the newspapers on his route in the first hour and 4/5 of the rest in the second hour what fraction of the n

Temka [501]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

Let the total number of Newspapers be x

Number of newspapers delivered in first hour of his route= $\frac{3}{8}$ of x

Total number of newspapers delivered in first hour= $\frac{3}{8}$ x

Number of newspapers left= x- $\frac{3x}{8}$

Number of newspapers left= $\frac{8x-3x}{8}$

Number of newspapers left= $\frac{5x}{8}$

Number of newspapers delivered in second hour=4/5 of $\frac{5x}{8}$

Number of newspapers delivered in second hour= $\frac{x}{2}$

Fraction of newspapers delivered in second hour is= $\frac{1}{2}$

Hence, the correct answer is $\frac{1}{2}$

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Prove that the diagonals of a parallelogram bisect each other

Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof : $\begin{array}{ |c| c | c | } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In \: \triangle ^{s} \:AOB \: and \: COD } \\ \sf{(i)}& \sf{ \angle \: OAB = \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\ \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\ \sf{(iii)} &\sf{ \angle \: OBA= \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\ \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}. Proved ✔$

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