10 + 15x + x + 10
= 16x + 20
The answers to the first two systems of equations
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
Step-by-step explanation:
35=-5t²+10t+22
5t²-10t+13=0
disc =b²-4ac=(-10)²-4×5×13=100-260=-160<0
t is imaginary.
So ball never reaches a height of 35 m
