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uysha [10]
4 years ago
12

Mike has $136 to spend at the amusement park. He spends 25% of that money on his ticket into the park. How much does Mike have l

eft to spend?
Mathematics
2 answers:
tekilochka [14]4 years ago
8 0
Hey there,

Question : <span>Mike has $136 to spend at the amusement park. He spends 25% of that money on his ticket into the park. How much does Mike have left to spend?

Answer : 
100 % = $136
1% = 136 / 100
      = $1.36
25% = $1.36 x 25
        = $34
Left = $136 - $34
       = $102

Hope this helps :))

<em>~Top♥</em>
</span>
Mandarinka [93]4 years ago
8 0
25% of 136 is 27.85.
Subtract 27.85 - 136.00 = 108.14
Mike has $108.14 left to spend.
Hope this helps!!!
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julia-pushkina [17]

Answer:

minimum -45, maximum 32

Step-by-step explanation:

C=4x-3y

x≥0, y≥4, x+y≤15

Maximum value of C can be achieved at max x and min y

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Minimum value of C can be achieved at min x and max y

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So answer is minimum -45, maximum 32

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3 years ago
Which of the following statements is true if m∠E = m∠Y and m∠F = m∠X?
mars1129 [50]

Answer:

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

Step-by-step explanation:

see the attached figure to better understand the problem  

we know that  

If m∠E = m∠Y and m∠F = m∠X  

then  

Triangles EFG and YXZ are similar by AA Similarity Theorem  

Remember that  

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent  

In this problem  

The corresponding sides are  

FE and XY  

EG and YZ  

GF and ZX  

so therefore  

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX Firstly , let us learn about trigonometry in mathematics.  

Suppose the ΔABC is a right triangle and ∠A is 90°.  

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

Let us now tackle the problem!  

A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.  

From the figure in the attachment , we can conclude that:  

m∠E = m∠Y  

m∠F= m∠X  

m∠G = m∠Z  

∴ ΔEFG ~ ΔYXZ  ( ΔEFG is similar to ΔYXZ )    

Because of the similarity , then:  

FE : XY = EG : YZ = GF : ZX  

Conclusion:

ΔFG is similar to ΔYXZ.  

Segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX , i.e:    

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

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Step-by-step explanation:

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IgorC [24]

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