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Alina [70]
3 years ago
13

A half-acre building lot is five times as long as it is wide. What are its dimensions?

Mathematics
1 answer:
Gnoma [55]3 years ago
6 0

we know that

A half-acre is equal to----------> 2,023.43\ m^{2}

Let

x---------> the length side of the building lot

y--------> the width side of the building lot

A------> Area of the building lot

x=5y-------> equation 1

A=2,023.43\ m^{2}

A=x*y

2,023.43=x*y --------> equation 2

substitute equation 1 in equation 2

2,023.43=[5y]*y

5y^{2}= 2,023.43\\y^{2}= 404.686\\y= 20.11\ m

<u>Find the value of x</u>

x=5y---> x=5*20.11--> x=100.55 m

therefore

<u>the answer is</u>

the dimensions of the building lot are 100.55 m* 20.11 m

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brainly.com/question/25354980

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