Question

A half-acre building lot is five times as long as it is wide. What are its dimensions?

Answer 1

we know that

A half-acre is equal to----------> $2,023.43\ m^{2}$

Let

x---------> the length side of the building lot

y--------> the width side of the building lot

A------> Area of the building lot

x=5y-------> equation 1

$A=2,023.43\ m^{2}$

$A=x*y$

$2,023.43=x*y$ --------> equation 2

substitute equation 1 in equation 2

$2,023.43=[5y]*y$

$5y^{2}= 2,023.43\\y^{2}= 404.686\\y= 20.11\ m$

Find the value of x

$x=5y---> x=5*20.11--> x=100.55 m$

therefore

the answer is

the dimensions of the building lot are 100.55 m* 20.11 m