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3 years ago

3.

Mathematics

1 answer:

lilavasa [31]3 years ago

4 0

Answer:

Step-by-step explanation:

Since there is 112 more red marbles than green marbles,

7 units= 112

1 unit= 112÷7= 16

2 units(no. of blue marbles)=16×2=32

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In the middle school coding club, 30% of the members are in 6th grade. If there are 12 sixth graders in the club, how many total

lisov135 [29]

Answer:

40 members

Step-by-step explanation:

Let the total members = x

Given the following data;

Number of sixth graders = 12 members

The mathematical expression is;

$\frac {30}{100} * x = 12$

$0.3x = 12$

$x = \frac {12}{0.3}$

x = 40

Therefore, the total members in the middle school coding club is 40 members.

5 0

3 years ago

Round 4.25 to the nearest tenth

kobusy [5.1K]

The 5 rounds to 3 so it is 4.3

7 0

3 years ago

Read 2 more answers

What is the difference between a parallelogram and a rhombus

Romashka-Z-Leto [24]

A parallelogram is a polygon with two sets of opposite, parallel sides.
A rhombus is a type of parallelogram with four congruent sides and angles but no right angles.

So, all rhombuses are parallelograms, but not all parallelograms are rhombuses.

5 0

3 years ago

Read 2 more answers

Please someone help me with the question

Yuki888 [10]

Answer:

$\displaystyle \frac{d}{dx}[e^{2x}] = 2e^{2x}$

$\displaystyle \frac{d}{dx}[e^{3x}] = 3e^{3x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Exponential Rule [Multiplying]: $\displaystyle b^m \cdot b^n = b^{m + n}$

Calculus

Derivatives

Derivative Notation

eˣ Derivative: $\displaystyle \frac{d}{dx}[e^x] = e^x$

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[e^x \cdot e^x]$

$\displaystyle \frac{d}{dx}[e^{3x}] = \frac{d}{dx}[e^x \cdot e^{2x}]$

Step 2: Differentiate

$\displaystyle \frac{d}{dx}[e^{2x}]$

[Derivative] Product Rule: $\displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[e^x]e^x + e^x\frac{d}{dx}[e^x]$
[Derivative] eˣ Derivative: $\displaystyle \frac{d}{dx}[e^{2x}] = e^x \cdot e^x + e^x \cdot e^x$
[Derivative] Multiply [Exponential Rule - Multiplying]: $\displaystyle \frac{d}{dx}[e^{2x}] = e^{2x} + e^{2x}$
[Derivative] Combine like terms [Addition]: $\displaystyle \frac{d}{dx}[e^{2x}] = 2e^{2x}$

$\displaystyle \frac{d}{dx}[e^{3x}]$

[Derivative] Product Rule: $\displaystyle \frac{d}{dx}[e^{3x}] = \frac{d}{dx}[e^x]e^{2x} + e^x\frac{d}{dx}[e^{2x}]$
[Derivative] eˣ Derivatives: $\displaystyle \frac{d}{dx}[e^{3x}] = e^x(e^{2x}) + e^x(2e^{2x})$
[Derivative] Multiply [Exponential Rule - Multiplying]: $\displaystyle \frac{d}{dx}[e^{3x}] = e^{3x} + 2e^{3x}$
[Derivative] Combine like terms [Addition]: $\displaystyle \frac{d}{dx}[e^{3x}] = 3e^{3x}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

8 0

3 years ago

Calculate the P-value for the given scenario. Use 4 decimal places.:

kvv77 [185]

Answer:

The p-value is 0.1867.

Step-by-step explanation:

Employees at a construction and mining company claim that the mean salary of the company's mechanical engineers is less than that of the one of its competitors, which is $68,000.

At the null hypothesis we test that the salary is the same of the competitor, that is:

$H_0: \mu = 68000$