Answer:
The answer to your question is 1.33 M
Explanation:
Data
Volume of H₃PO₄ = 24 ml
[H₃PO₄] = ?
Volume of KOH = 16 ml
[KOH] = 2 M
1 M H₃PO₄ = 3.0 M H⁺
Balanced chemical reaction
KOH + H₃PO₄ ⇒ K₃PO₄ + H₂O
Process
1.- Calculate the moles of KOH
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = 2 x 16/1000
-Simplification
moles = 32/1000
-Result
moles = 0.032
2.- Calculate the moles of H₃PO₄
1 mol of KOH --------------- 1 mol of H₃PO₄
0.032 moles of KOH -------------- x
x = (0.032 x 1) / 1
x = 0.032 moles of H₃PO₄
3.- Calculate the concentration of H₃PO₄
Molarity = 0.032 / 0.024
-Result
Molarity = 1.33
