Answer:
Br2(l) → BrO3-(aq) + Br-(aq)
A) Br2 = 3, OH - = 6
B) Br2 = 3, OH - = 3
C) Br2 = 2, OH - = 5
D) Br2 = 1, OH - = 2
E) Br2 = 1, OH - = 6
Answer:
There are five signs of a chemical change:
Colour Change.
Production of an odour.
Change of Temperature.
Evolution of a gas (formation of bubbles)
Precipitate (formation of a solid).
239.0 g/mol
Add the mass of each individual atom
Answer:
-0.050 kJ/mol.K
Explanation:
- A certain reaction is thermodynamically favored at temperatures below 400. K, that is, ΔG° < 0 below 400. K
- The reaction is not favored at temperatures above 400. K, that is. ΔG° > 0 above 400. K
All in all, ΔG° = 0 at 400. K.
We can find ΔS° using the following expression.
ΔG° = ΔH° - T.ΔS°
0 = -20 kJ/mol - 400. K .ΔS°
ΔS° = -0.050 kJ/mol.K
