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2 years ago

What are the non-living components of an ecosystem? The non-living components of an ecosystem are factors.

Chemistry

2 answers:

White raven [17]2 years ago

4 0

The answer is: abiotic factors.

Abiotic factors are non-living chemical and physical things of the environment.

On the contrary, biotic factors are all of the living organisms within an ecosystem.

Abiotic factors can include water, light, radiation, temperature, humidity, atmosphere, and soil.

For example, abiotic factors found in terrestrial ecosystems are sunlight, rain, wind, temperature, soil, pollution, nutrients, pH of soil and water, types of soil.

Nina [5.8K]2 years ago

4 0

Answer:

abiotic

Explanation:

got it right on plato!

You might be interested in

How many moles of H2O2 are needed to react with 1.07 moles of N2H4?

I am Lyosha [343]

Answer:

2.14 moles of H₂O₂ are required

Explanation:

Given data:

Number of moles of H₂O₂ required = ?

Number of moles of N₂H₄ available = 1.07 mol

Solution:

Chemical equation:

N₂H₄ + 2H₂O₂ → N₂ + 4H₂O

now we will compare the moles of H₂O₂ and N₂H₄

N₂H₄ : H₂O₂

1 : 2

1.07 : 2×1.07 = 2.14 mol

6 0

2 years ago

Test Yourself

Alenkasestr [34]

Answer:

billion is larger \ part if billion

6 0

2 years ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

What is the factor of 1024

Ugo [173]

1
2
4
8
16
32
64
128
256
512
1024

4 0

2 years ago

What's the difference between gold and other metals

Zanzabum

Well, gold is way different form other say for instance what if you get a really good ring not to expensive or cheap, but its in between those characteristics what if u get a gold ring to compare now one might tarnish or fade, but if you really look at it that gold one will not it really all dependents on what metals your talking about cause all metals aren't the same some fade and some don't . Also the oxygen level is weak for other metals, but gold it different it can still keeps its shine .

- That's the best explanation i can give IF ITS NOT ENUH OR NOT RIGHT JUH COMMENT BELOWW↓↓ I WILL THINK OF SOMEThING ELSE THANKS! YOU HAVE A GREAT DAYY .

5 0

2 years ago