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guapka [62]
3 years ago
9

What are the non-living components of an ecosystem? The non-living components of an ecosystem are factors.

Chemistry
2 answers:
White raven [17]3 years ago
4 0

The answer is: abiotic factors.

Abiotic factors are non-living chemical and physical things of the environment.

On the contrary, biotic factors are all of the living organisms within an ecosystem.

Abiotic factors can include water, light, radiation, temperature, humidity, atmosphere, and soil.

For example, abiotic factors found in terrestrial ecosystems are sunlight, rain, wind, temperature, soil, pollution, nutrients, pH of soil and water, types of soil.

Nina [5.8K]3 years ago
4 0

Answer:

abiotic

Explanation:

got it right on plato!

You might be interested in
How many grams of 02 will be formed from 6.5 moles of KCLO3
Allisa [31]

Answer:

312 g of O₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO₃ —> 2KCl + 3O₂

From the balanced equation above,

2 mole of KClO₃ decomposed to 3 moles of O₂.

Next, we shall determine the number of mole of O₂ produced by the reaction of 6.5 moles of KClO₃. This can be obtained as follow:

From the balanced equation above,

2 mole of KClO₃ decomposed to 3 moles of O₂.

Therefore, 6.5 moles of KClO₃ will decompose to produce = (6.5 × 3)/2 = 9.75 moles of O₂.

Finally, we shall determine the mass of 9.75 moles of O₂. This can be obtained as follow:

Mole of O₂ = 9.75 moles

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ =?

Mole = mass / Molar mass

9.75 = Mass of O₂ / 32

Cross multiply

Mass of O₂ = 9.75 × 32

Mass of O₂ = 312 g

Thus, 312 g of O₂ were obtained from the reaction.

4 0
3 years ago
Read 2 more answers
Element Q is a theoretical nonmetal with atomic number 59. Consider the isotope: Q-95. How many electrons are in an atom of Q-95
Vinil7 [7]

60

Explanation:

The number of electrons in an atom of Q-95 will be 60 electrons.

The atomic number of an atom is the number of protons in the atom of the isotope

This number is unique to every atom and their isotope

An isotope of an atom is the existence of an atom having the same atomic number but different mass numbers.

Since atomic number the same as number of protons, they are the positively charged particles in an atom.

To have a negative charge, the number of electrons must be more than that of protons.

Charge = number of protons - number electrons

  charge = -1

  -1 = 59  - number of electrons

  Number of electrons = 60 electrons

learn more:

Number of subatomic particles brainly.com/question/2757829

#learnwithBrainly

4 0
3 years ago
4. A sample of gas has a pressure of 700 mmHg and 30.0°C. Ar what temperature would the pressure be 600 mmHg if the volume remai
shtirl [24]

Answer:

T₂  = 259.84 K

T₂  = -13.31 °C

Explanation:

Given data:

Initial pressure = 700 mmHg

Initial temperature = 30.0°C (30+273.15 K = 303.15 K)

Final temperature = ?

Final pressure = 600 mmHg

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

700 mmHg /303.15 K  = 600 mmHg / T₂

T₂  = 600 mmHg × 303.15 K / 700 mmHg

T₂  =181890 mmHg.K /700 mmHg

T₂  = 259.84 K

Temperature in celsius

259.84 K - 273.15 = -13.31 °C

7 0
3 years ago
Which statement best illustrates vibrational motion?
jekas [21]
C. Cello playing music at a concert
8 0
3 years ago
Read 2 more answers
if three oxygen particles are needed to form ozone, how many units of ozone could be formed from 6 oxygen particles? from 9? fro
tensa zangetsu [6.8K]
<h3>Answers:</h3>

             1) 2 Units of Ozone

             2)  3 Units of Ozone

              3)  9 Units of Ozone

<h3>Solution:</h3>

1)  From 6 Oxygen Particles;

As given,

                          3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      6 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (6 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  2 Units of Ozone

2) From 9 Oxygen Particles;

As given,

                           3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      9 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (9 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  3 Units of Ozone

3)  From 27 Oxygen Particles;

As given,

                             3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      27 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (27 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  9 Units of Ozone

3 0
3 years ago
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