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guapka [62]
3 years ago
9

What are the non-living components of an ecosystem? The non-living components of an ecosystem are factors.

Chemistry
2 answers:
White raven [17]3 years ago
4 0

The answer is: abiotic factors.

Abiotic factors are non-living chemical and physical things of the environment.

On the contrary, biotic factors are all of the living organisms within an ecosystem.

Abiotic factors can include water, light, radiation, temperature, humidity, atmosphere, and soil.

For example, abiotic factors found in terrestrial ecosystems are sunlight, rain, wind, temperature, soil, pollution, nutrients, pH of soil and water, types of soil.

Nina [5.8K]3 years ago
4 0

Answer:

abiotic

Explanation:

got it right on plato!

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Margaret [11]

No thanks. I dont buy drugs

5 0
3 years ago
The solubility of substance (Z) is 40g/100ml of water at 25°C. A)Can you
anyanavicka [17]

Answer:

No, It would be a unsaturated solution

Explanation:

The solubility of a compound gives us information about how a compound may dissolve or not in a determinate solvent.

In this case we have Z, which in 25 °C the solubility of this compound is 40g/100 mL water. This means that if we have 60 g of Z and try to dissolve it in 100 mL of water, only 40 g of Z will solve and the remaining 20 g will be in the water as precipitate or remaining solid.

Now if you just put 40 g of Z in 100 mL water, it will dissolve completely in water, and in this case, we have a saturated solution. A saturated solution is when you dissolve a determinated quantity of a solute in a determinated quantity of solvent, without remaining of solid or excess of solvent.

According to this explanation, we now have 120 g of Z. To make a saturated solution of Z with this quantity, well, let's do math. If 40 g dissolves in 100 mL, then 80 g would be 200 mL and 120 g would have to be 300 mL of water. But in this case, we have 450 mL of water, we have more than 300 mL, an excess of water, so, the 120 g will dissolve but it's dissolved in more than the needed quantity to be a saturated solution, therefore, we have an unsaturated solution of Z (more solvent than the needed).

Hope this helps.

8 0
3 years ago
Calculate the rms speed of an oxygen gas molecule, o2, at 17.0 ∘c .
ludmilkaskok [199]
The  RMS  of O2  at  17  degrees   is  calculated  as  follows

RMs= ( 3RT/m)^1/2   where

R= ideal  gas   constant  =  8.314
T=   temperature=   17+273=  290 K
M=  molar  mass   in  KG =   32/1000=  0.032  Kg

Rms  is  therefore= sqrt (3x   8.314  x290/0.032 )  =  sqrt( 226036.875

RMs=475.43

6 0
3 years ago
Read 2 more answers
Calculate the pH at of a 0.10 Msolution of anilinium chloride . Note that aniline is a weak base with a of . Round your answer t
notsponge [240]

The question is incomplete, here is the complete question:

Calculate the pH at of a 0.10 M solution of anilinium chloride (C_6H_5NH_3Cl) . Note that aniline (C6H5NH2) is a weak base with a pK_b of 4.87. Round your answer to 1 decimal place.

<u>Answer:</u> The pH of the solution is 5.1

<u>Explanation:</u>

Anilinium chloride is the salt formed by the combination of a weak base (aniline) and a strong acid (HCl).

To calculate the pH of the solution, we use the equation:

pH=7-\frac{1}{2}[pK_b+\log C]

where,

pK_b = negative logarithm of weak base which is aniline = 4.87

C = concentration of the salt = 0.10 M

Putting values in above equation, we get:

pH=7-\frac{1}{2}[4.87+\log (0.10)]\\\\pH=5.06=5.1

Hence, the pH of the solution is 5.1

8 0
3 years ago
What is condensation ​
sveta [45]

Answer:

condensation is when a gas becomes a liquid

Explanation:

4 0
4 years ago
Read 2 more answers
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