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____ [38]
3 years ago
8

Write 10 to the 2nd power as a decimal​

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

i would guess it would be 100.0

if it was 10 negative 2nd power it would make mor sense bc it would be 0.01

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The number 6 is 30% of what number
alexandr402 [8]
6 and 3000 is the answer for ur question would be 3000
8 0
3 years ago
If m is a common divisor of x and y, then x/y = (x ÷ k)/______
myrzilka [38]

Answer:

\frac{x}{y} = \left(\frac{x}{y} \right)\cdot 1 = \left(\frac{x}{y}\right)\cdot \left(\frac{m}{m} \right) = \frac{\frac{x}{m} }{\frac{y}{m} }

Step-by-step explanation:

The common divisor is the greatest natural number so that two or more natural numbers have no remainder. If m is a common divisor of x and y, then p = \frac{x}{m} and q = \frac{y}{m}, where p, q \in \mathbb{Z}. Then, we have the following expression:

\frac{x}{y} = \left(\frac{x}{y} \right)\cdot 1 = \left(\frac{x}{y}\right)\cdot \left(\frac{m}{m} \right) = \frac{\frac{x}{m} }{\frac{y}{m} }

3 0
3 years ago
An experimenter conducted a two-tailed hypothesis test on a set of data and obtained a p-value of 0.44. If the experimenter had
Lyrx [107]

Answer:

Correct option is (C).

The possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.

Step-by-step explanation:

The <em>p</em>-value is the probability of acquiring a result as extreme as the observed result, assuming the null hypothesis statement is true.

The <em>p</em> value of a test is:

Left-tailed test: P(TS

Right-tailed test: P(TS>ts) = 1- P(TS.

Here,

TS = Test statistic

ts = computed value of the test statistic.

The two-tailed <em>p</em>-value is: 2P(TS or 2P(TS>ts).

The <em>p</em>-value of the two tailed test is, 0.44.

Compute the <em>p</em>-value for one-tailed test a follows:

  • For a left-tailed test:

            2P(TS

  • For a right-tailed test:

            P(TS>ts) = 1- P(TS

Thus, the possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.

The correct option is (C).

3 0
3 years ago
PLS HELP!! AND HURRY!! Find an expression for the nth term ( tn ) in each of the following sequences:
fiasKO [112]

If the pattern continues, so that each term is separated by a distance of 3, then the sequence is given by the recursive rule

\begin{cases}a_1=1\\a_n=a_{n-1}+3&\text{for }n>1\end{cases}

From this definition, we can write a_n in terms of a_1:

a_2=a_1+3

a_3=a_2+3=(a_1+3)+3=a_1+2\cdot3

a_4=a_3+3=(a_1+2\cdot3)+3=a_1+3\cdot3

a_5=a_4+3=(a_1+3\cdot3)+3=a_1+4\cdot3

and so on, up to

a_n=a_1+(n-1)\cdot3

(notice how the subscript on <em>a</em> and coefficient on 3 add up to <em>n</em>)

or

a_n=1+3(n-1)=3n-2

6 0
3 years ago
(2x + y) (2x + 2y) =
IceJOKER [234]

Answer: 4x^2 + 6xy + 2y^2

Step-by-step explanation:

(2x + y)(2x + 2y) =

2x*2x + 2x*2y + y*2x + y^2y =

4x^2 + 4xy + 2xy + 2y^2 =

4x^2 + 6xy + 2y^2

3 0
3 years ago
Read 2 more answers
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