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____ [38]
2 years ago
8

Write 10 to the 2nd power as a decimal​

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
3 0

Answer:

i would guess it would be 100.0

if it was 10 negative 2nd power it would make mor sense bc it would be 0.01

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Vesnalui [34]

Answer:

\frac{1}{12}X

Step-by-step explanation:

Let X is the number of hours Larry works a day

Given:  Larry spends half of his workday teaching piano lessons.

=> Number of hours he teaches piano a day is: \frac{1}{2}X

As we know that, he has 6 students, so the fraction of his workday is spent with each student is:

\frac{1}{2}X : 6

= \frac{1}{12}X

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2 years ago
I need help asap. anyone?
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Answer:

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-(9-15)+(-8+2)-(24-30)=
AleksAgata [21]
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2 years ago
The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0
3 years ago
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