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Eduardwww [97]
3 years ago
8

The length of a rectangle is (6x2 + 3x - 2) units, and its width is (x3 - 2x + 5) units. Part A: What is the area of the rectang

le? Show your work.
Part B: Does the answer for Part A show that polynomials are closed under an operation? Justify your answer.

Part C: What is the degree and classification of the expression obtained in Part A?
Mathematics
1 answer:
strojnjashka [21]3 years ago
6 0
<span>Part A: Area = length * width = (6x^2 + 3x - 2) * (x^3 - 2x + 5) Multiply it out and simplify.

part B: </span><span>Take the first term 6x^2 and multiply each of the term x^3, -2x & 5. Then take 3x and multiply each of the term x^3, -2x & 5. Do the same with -2. Then add like terms and simplify.</span>
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Let us take the number be x.

A number : x

A number divided by three : $\frac{x}{3}

A number divided by three less two : $\frac{x}{3}-2

A number divided by three less two is at most two : $\frac{x}{3}-2\leq 2

Now, simplify the inequality,

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Multiply by 3 on both sides of the equation,

$\Rightarrow\frac{x}{3}\times3\leq 4\times3

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