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Eduardwww [97]
3 years ago
8

The length of a rectangle is (6x2 + 3x - 2) units, and its width is (x3 - 2x + 5) units. Part A: What is the area of the rectang

le? Show your work.
Part B: Does the answer for Part A show that polynomials are closed under an operation? Justify your answer.

Part C: What is the degree and classification of the expression obtained in Part A?
Mathematics
1 answer:
strojnjashka [21]3 years ago
6 0
<span>Part A: Area = length * width = (6x^2 + 3x - 2) * (x^3 - 2x + 5) Multiply it out and simplify.

part B: </span><span>Take the first term 6x^2 and multiply each of the term x^3, -2x & 5. Then take 3x and multiply each of the term x^3, -2x & 5. Do the same with -2. Then add like terms and simplify.</span>
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Which translation maps the graph of the function fx=x2 onto the function gx= x2+(-8x)+7
Olin [163]

Answer:

<h2>Shift the graph of f(x) 4 units to the right</h2><h2>and 7 units up</h2>

Step-by-step explanation:

f(x) + n - shift a graph of f(x) n units up

f(x) - n - shift a graph of f(x) n units down

f(x + n) - shift a graph of f(x) n units to the left

f(x - n) - shift a graph of f(x) n units to the right

=============================================

We have

f(x)=x^2,\ g(x)=x^2+(-8x)+7

Convert the equation of g(x) to the vertex formula:

y=a(x-h)^2+k

g(x)=x^2+(-8x)+7\\\\g(x0=x^2-2(x)(4)+7\\\\g(x)=\underbrace{x^2-2(x)(4)+4^2}-4^2+7\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\g(x)=(x-4)^2+7=f(x-4)+7\\\\\text{shift the graph of f(x) 4 units to the right and 7 units up}

8 0
3 years ago
Find the area of the composite figure.
vodka [1.7K]

Answer:

25

Step-by-step explanation:

x = (5(3)) + (5(2))

x = 15 + 10

x = 25

4 0
2 years ago
When this 3 digit number is rounded to the nearest hundred it rounds to 900. The digit in the ones is the fifth odd number you c
garri49 [273]
859....9 is the 5th odd and you know the number is in the 800s so just add 9 and 8 and subtract from 22 and you get 5
3 0
3 years ago
Can you guys please help me with 3 and 4 I really need help I will give you 14 points
AURORKA [14]
For answer #3...
just replace (T) with 76.50 in the equation T=9h
Then since this is a division problem you would do 76.50/9=9h/9
This gives you your answer which is h=8.5.
Hope this helps!!:)
6 0
3 years ago
Akio found 18 cents in his pocket. He found 6 more coins in his pocket. Altogether he has 73 cents. What were the 6 coins he fou
Dafna1 [17]

Answer:

1 quarter, 1 dime, and 4 nickels

Step-by-step explanation:

First you subtract the 18 cents that were found in the pocket from the total amount of 73 cents to get the total amount of the 6 other coins:

73-18=55.

So the total amount of the 6 coins equals 55 cents.

The quarter = 25 cents

The dime = 10 cents

The 4 nickels =  5 + 5 + 5 + 5 = 20

1 quarter, 1 dime, and 4 nickels add up to the necessary total of 6 coins and when you add up the total cents of the quarter, dime, and nickels, 25 + 10 + 20 it comes to the sum of 55, which is how much the 6 coins are worth in total.

So therefore, the answer is 1 quarter, 1 dime, and 4 nickels.

8 0
3 years ago
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