Solubility of a gas in a liquid is directly proportional to the partial pressure of that gas above the liquid. Solubility of a gas is inversely proportional to temperature.
So, the solubility of carbon dioxide gas in water is increased by increasing the partial pressure of carbon dioxide and by decreasing the temperature.
Answer:
c
Explanation:
in kc we only consider gases and aquas not solids and liquids
Answer:
Mass percent N₂ = 89%
Mass percent H₂ = 11%
Explanation:
First we <u>use PV=nRT to calculate n</u>, which is the total number of moles of nitrogen and hydrogen:
- 1.03 atm * 7.45 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305 K
So now we know that
- MolH₂ + MolN₂ = 0.307 mol
and
- MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49 g
So we have a <u>system of two equations and two unknowns</u>. We use algebra to solve it:
Express MolH₂ in terms of MolN₂:
- MolH₂ + MolN₂ = 0.307 mol
Replace that value in the second equation:
- MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49
- (0.307-MolN₂) * 2 + MolN₂ * 28 = 3.49
- 0.614 - 2MolN₂ + 28molN₂ = 3.49
Now we calculate MolH₂:
- MolH₂ + MolN₂ = 0.307 mol
Finally, we convert each of those mol numbers to mass, to <u>calculate the mass percent</u>:
- N₂ ⇒ 0.111 mol * 28 g/mol = 3.108 g N₂
- H₂ ⇒ 0.196 mol * 2 g/mol = 0.392 g H₂
Mass % N₂ = 3.108/3.49 * 100% = 89.05% ≅ 89%
Mass % H₂ = 0.392/3.49 * 100% = 11.15% ≅ 11%
Answer:
remains constant regardless of the pH
Explanation:
The pH refers to the hydrogen potential or hydrogen power that states the aqueous solution acidity. It varies from 0 to 14. The higher pH values denotes more basic solutions while on the other hand, the lower pH values denote more acidic
An acidic solution refers to a solution at which the hydrogen ions concentration is more than the hydroxide ions concentration
Therefore the ion product of water remains constant as the value of both hydrogen ions and hydroxide ions is relatively small as non-dissociated water concentration would remain the same.
Hence, the second option is correct
It belongs to the “s-block”