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irina1246 [14]
3 years ago
8

in the reaction, 2h2 o2 --> 2h2o, how many hydrogen molecules are needed to produce two water molecules?a. 1b. 2c. 3d. 4

Chemistry
2 answers:
natali 33 [55]3 years ago
7 0
The balanced reaction between Hydrogen and Oxygen to form Water:

 2H₂ + O₂  →  2H₂O

From the equation it already states that:

2 molecules of Hydrogen H₂ are needed to produce 2 molecules of Water H₂O

So the answer is 2.

Option B.
Jlenok [28]3 years ago
4 0

Answer:

b. 2

There are necessary 2 hydrogen molecules to produce 2 water molecules.

Explanation:

The balanced equation is already given:

2H_{2} + O_{2} ->2H_{2}O

So, 2 molecules of diatomic hydrogen react with 1 molecule of diatomic oxygen to obtain 2 water molecules.

As you can see in the attached image, the 2 molecules of diatomic hydrogen have 2 hydrogen atoms each (i.e. 4 hydrogen atoms), the molecule of diatomic oxygen has 2 oxygen atoms and the 2 water molecules have 2 hydrogen atoms and 1 oxygen atom each (i.e. 4 hydrogen atoms and 2 oxygen atoms)

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Anvisha [2.4K]

Answer:Ionic compounds form when positive and negative ions share electrons and form an ionic bond. ... The positive ion, called a cation, is listed first in an ionic compound formula, followed by the negative ion, called an anion. A balanced formula has a neutral electrical charge or net charge of zero.

Explanation:Simple ions:  

Perchlorate ClO4- IO3-

Chlorate ClO3- BrO3-

Chlorite ClO2-  

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7 0
3 years ago
How does a balanced chemical equation demonstrate conservation of mass?
Mariulka [41]

Answer:

A balanced chemical equation will demonstrate the law of conservation of mass because the amount of elements on one side (reactants) will equal the amount of elements on the other side (products).

Explanation:

CH₄ + 4Cl₂ -> CCl₄ + 4HCl

Reactants:

1 C

4 H

8 Cl

Products:

1 C

4 H

8 Cl

6 0
3 years ago
Read 2 more answers
Problem PageQuestion A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of
igomit [66]

Answer:

5.37 × 10⁻⁴ mol/L

Explanation:

<em>A chemist makes 660. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a 0.00154 mol/L stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.</em>

Step 1: Given data

  • Initial concentration (C₁): 0.00154 mol/L
  • Initial volume (V₁): 230. mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 660. mL

Step 2: Calculate the concentration of the final solution

We want to prepare a dilute solution from a concentrated one. We can calculate the concentration of the final solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 0.00154 mol/L × 230. mL / 660. mL = 5.37 × 10⁻⁴ mol/L

5 0
3 years ago
Plz help. I just need someone to check answer. :(
My name is Ann [436]
These substances can be separated by distillation, so your answer is A.
5 0
3 years ago
What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?
Marina86 [1]

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

6 0
3 years ago
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