Bellow you my find the chemical equations of the ionization of a triprotic acid.
Explanation:
The chemical equations for the ionization of phosphoric acid (H₃PO₄), which is a triprotic acid, in water:
H₃PO₄ (s) + H₂O (l) → H₂PO₄⁻ (aq) + H₃O⁺ (aq)
H₂PO₄⁻ (aq) + H₂O (l) → HPO₄²⁻ (aq) + H₃O⁺ (aq)
HPO₄²⁻ (aq) + H₂O (l) → PO₄³⁻ (aq) + H₃O⁺ (aq)
where:
(s) - solid
(l) - liquid
(aq) - aqueous
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triprotic acid
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Answer:
1, 2, 4
Explanation:
The primitive cubic unit cell has eight corners, and each corner is shared with 8 cubic unit cells. Therefore since we have one atom at each corner, we will have:
8 corner x 1 atom/8 corner = 1 atom
There is then the equivalent of one atom per unit cell in the primitive cubic cell.
For the body-centered cubic unit cell, we have 8 corners again shared each by 8 lattices as in the simple cubic plus we have one atom in the center of the cubic lattice. Therefore, the number of atoms in the body -centerd unit cell is two:
8 corner x 1 atom/8 corner = 1 atom
+
1 atom in the center
= 2 atoms/ unit cel
For the face-centerd cubic again we have 8 atoms in the corners shared by 8 lattices, plus 1 atom in each of the faces shared by two unit cells:
8 corner x 1/8 atom/corner + 6 faces x 1 atom/face = 4 atoms/unit cell
635ml will yield 1m of hcl
xml will yield 10m of hcl
that means 6250ml will yield 10m of hcl
Over land or over cooler water they start to lose their power
Answer:
171.34 g/mol
Explanation:
Ba molar mass = 137.328 g/mol
O molar mass = 15.999 g/mol * 2 = 31.9980 g/mol
H molar mass = 1.008 g/mol * 2 = 2.0160 g/mol
137.328 + 31.9980 + 2.0160 = 171.3420 = 171.34 g/mol