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RUDIKE [14]
2 years ago
10

Which would be larger, fluorine atomic radius or fluorine Ionic radius. Explain

Chemistry
2 answers:
dmitriy555 [2]2 years ago
4 0

Answer:

Fluorine has the atomic number which contain protons and electrons. ... As the number of electrons is increased, the nuclear force of attraction is decreased. Thus, the radius of fluoride ions is larger than that of fluorine atoms.

Explanation:

Alex2 years ago
4 0
The ionic radius of fluoride is much larger than its covalent radius. When F becomes F−, it gains one electron but has the same number of protons, meaning the attraction of the protons to the electrons is weaker, and the radius is larger.
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Lipoamide is a covalently attached coenzyme that plays a key role in several decarboxylase reactions, including glycine decarbox
Reika [66]

Answer:

Lysine 63.

Explanation:

The coenzyme may be defined as the non protein part of an enzyme that plays an important role in the enzyme functioning. Any cation or small molecule like amino acids can acts as coenzyme.

Lipoamide is important coenzyme that plays an important role in the metabolic pathways by undergoes the decarboxylation reactions. The reduced lipoamide known as dihydrolipoamide is used for the covalent attachment at Lysine 63 residues.

Thus, the correct answer is option (D).

3 0
3 years ago
Would you rather play warfare of play fortnight
kakasveta [241]

Answer:

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Explanation:

5 0
3 years ago
A 1000-ml bag of d5w 1/2 ns is to infuse over 8 hours. what is the flow rate of the infusion?
AlladinOne [14]
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7 0
3 years ago
Choose all of the answers that are correct when describing this atom.
gregori [183]
I believe that this atom is  chlorine and the atom has an overall charge of zero.
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4 0
3 years ago
Read 2 more answers
after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 2
Alexxandr [17]
Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
 the number of the mol solute

22.0 g AgNO3 * \frac{1 mol AgNO3}{169.91 g AgNO3} = 0.129 mol AgNO3

2) 725 ml = 0.725 L




3) Molarity = \frac{number/ mol/solute}{Volume/solution} = \frac{0.129}{0.725} 



Molarity= \frac{0.178 mol}{L} , 

or 0.178 M



3 0
3 years ago
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