Answer:
Explanation:
Hello,
In this case, for the given reaction, the equilibrium constant turns out:
![Keq=\frac{[B]}{[A]}=\frac{0.5M}{1.5M} =1/3](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BB%5D%7D%7B%5BA%5D%7D%3D%5Cfrac%7B0.5M%7D%7B1.5M%7D%20%3D1%2F3)
Nonetheless, we are asked for the reverse equilibrium constant that is:
Which is greater than one.
In such a way, the Gibbs free energy turns out:
Now, since the reverse equilibrium constant is greater than zero its natural logarithm is positive, therefore with the initial minus, the Gibbs free energy is less than zero, that is, negative.
<u>We are given:</u>
Initial Temperature = 90°c
Final Temperature = 120°c
Heat applied(ΔH) = 500 Joules
Specific heat(c) = 0.9 Joules / g°C
Mass of Aluminium(m) = ?
<u>Change in temperature:</u>
ΔT = Final temp. - Inital Temp.
ΔT = 120 - 90
ΔT = 30°c
<u>Calculating the mass:</u>
We know the formula:
ΔH = mcΔT
replacing the values:
500 = m(0.9)(30)
500 = m(27)
m = 500/27
m = 18.52 grams
I believe that the answer is A. Decaying
Answer:
Explanation:
how many grams and moles of gold are present in 8.09 x 10^28 atoms of gold?
there are 6.02 x 10^23 molecules or atoms in 1 mole
of a compound or element
8.09 x 10^28 /(6.02 x 10^23) = 1.34 x 10^5 moles of Au
1 mole of gold (see periodic table for #79) 197 g
so 1.34 x 10^5 moles of Au weigh
197 x 1.34 x 10^5 = 2.64 x 10^7 g
your little gold treasure is worth
Gold Price Per Gram $59.87 x 2.64 x 10^7=
$$$$ 1.58 x 10^9
=$ 1,580,000,000
:<span> </span><span>4 HCl + MnO2 → MnCl2 + 2 H2O + Cl2
(33.7 g MnO2) / (86.93691 g MnO2/mol) = 0.38764 mol MnO2
(45.3 g HCl) / (36.4611 g HCl/mol) = 1.2424 mol HCl
(a)
1.2424 moles of HCl would react completely with 1.2424 x (1/4) = 0.3106 mole of MnO2, but there is more MnO2 present than that, so MnO2 is in excess and HCl is the limiting reactant.
(b)
(1.2424 mol HCl) x (1 mol Cl2 / 4 mol HCl) x (70.9064 g Cl2/mol) = 22.0 g Cl2
(c)
(77.7% of 22.0 g Cl2) = 17.1 g Cl2</span>
