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lianna [129]
3 years ago
5

When a 0.740-g sample of trinitrotoluene (TNT), C7H5N2O6, is burned in a bomb calorimeter, the temperature increases from 23.4 °

C to 26.9 °C. The heat capacity of the calorimeter is 534 J/°C, and it contains 675 mL of water. How much heat was produced by the combustion of the TNT sample?
Chemistry
1 answer:
Kisachek [45]3 years ago
7 0

Answer:

The answer to your question is: Q = 1383.06 J

Explanation:

Data

mass = 0.740 g

Initial Temperature = 23.4°

Final Temperature = 26.9°

Cp = 534 J/°C

mass of water = 675 ml

Q = ?

Formula

Q = mCpΔT

Process

Q = (0.740)(534) (26.9 - 23.4)

Q = (0.740)(534) (3.5)

Q = 1383.06 J

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\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

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n = m/M; 0.6498 \; g of the first compound would contain

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Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

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3 years ago
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The symbol for it is M, and it serves as one of the most often used concentration units. Its definition states how many moles of solute there are in a liter of solution.

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