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lions [1.4K]
3 years ago
11

The substrate is the same in parts a and b, however the mechanism that proceeds is different. Explain how the choice of solvent

(acetone vs. methanol) influences the reaction mechanism between benzyl bromide and a nucleophile.
Chemistry
1 answer:
GenaCL600 [577]3 years ago
3 0

Answer:

See explanation

Explanation:

The reaction of a benzyl bromide with a nucleophile may proceed by SN1 or SN2 mechanism depending on the nature of the solvent used.

Since SN1 reaction involves the formation of a carbocation, it usually predominates in the presence of a poor nucleophiles and protic solvents. Hence when methanol is used as solvent and a poor nucleophile is used, SN1 mechanism predominates.

However, when acetone which is an aprotic solvent is used in the presence of a good nucleophile, SN2 reaction mechanism predominates.

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Write the equation for a rn-224 atom undergoing 1 beta decay: what is the daughter?
gayaneshka [121]

Answer:

Rn-224 --> Fr-224 + beta

Explanation:

Hi

When an isotope of radon 224 undergoes a radioactive decay by emitting a beta particle, an isotope of francium 224 is obtained.

Remember that the first letter of a chemical symbol is written with a capital letter .

Radon: Rn

Francium: Fr

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7 0
3 years ago
What would the ionic formula be for the following ionic compound:
skad [1K]
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6 0
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Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy for the following redox
stealth61 [152]

Answer:

-973 KJ

Explanation:

The balanced reaction equation is;

N2H4(aq) + 2Cl2(g) + 4OH^-(aq)---------> 4Cl-(aq) + 4H ^+(aq) + 4OH^-(aq) + N2(g)

Reduction potential of hydrazine = -1.16 V

Reduction potential of chlorine = 1.36 V

From;

E°cell= E°cathode - E°anode

E°cell= 1.36 - (-1.16)

E°cell= 2.52 V

∆G°=- nFE°cell

n= number of moles of electrons = 4

F= Faraday's constant = 96500 C

E°cell = 2.52 V

∆G°=- (4 × 96500 × 2.52)

∆G°= -972720 J

∆G°= -972.72 KJ

7 0
4 years ago
The ion mn2+ has how many unpaired electrons
photoshop1234 [79]
It has 5 unpaired electrons
3 0
3 years ago
2H2 + O2 → 2H2O
pantera1 [17]
Okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles

moles of O2 is half
so 40.04 x 0.5
20.02moles

grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g

6 0
3 years ago
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