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galben [10]
3 years ago
6

What was the final price of the wind chime?

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

$29.93

Step-by-step explanation:

First, we take the discount off of the original price.

We need to find the discount amount in dollars.

30/100=.3 this is 1%.

.3 * 5 = 1.5 He will get $1.50 off of his purchase.

30 - 1.5 = 28.5.

Next we will add tax. We need to find tax in dollars.

28.5/100=.285 this is 1%

.285 * 5 = 1.43 He will get $1.43 of tax on his purchase.

28.5 + 1.43 = 29.93

He will pay $29.93 for his wind chime.

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
1. Does this equation represent growth or decay?<br> A (t) = 800(1.21)
Sholpan [36]

Answer:Decay

Step-by-step explanation: because of perenthesis

6 0
3 years ago
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The graph represents the data cost for monthly internet service for a cell phone. Which function, C(x), respresent the monthly c
Tanya [424]

Answer:

Correct option: first one

Step-by-step explanation:

The graph has 3 different parts:

Cost = 15 when the Gigabytes used is lesser than or equal 2,

Cost from 20 to 40 when the Gigabytes used is greater than 2 and lesser than or equal 6.

An increase of 4 gigabytes caused an increase of 20 in the cost, so the slope is 20/4 = 5, and the y-intercept is:

20 = 5*2 + b -> b = 10

Cost = 50 when the Gigabytes used is greater than 6.

So the correct option is the first one

3 0
3 years ago
What is the area of this tile 6in 2in
OlgaM077 [116]

Answer:

12

Step-by-step explanation:

6in x 2in = 12

6 0
3 years ago
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The seventh grade boys at colonial Christian school removed 1/3 of the 558 chairs in the auditorium how many chairs did they rem
vekshin1
558 * 1/3 = 186
186 chairs
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