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3 years ago

13

Please help!!!!!!!!!

1 answer:

uranmaximum [27]3 years ago

8 0

Is there any choices because i got 2 solutions

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What is the value of b^2 - 4ac for the following equation?

WINSTONCH [101]

(7)^2-4(5)(-6)=

49+120=169 is the answer

5 0

4 years ago

Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s

notsponge [240]

Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

No-show rate of 10%.

This means that $p = 0.1$

Four travelers who have made hotel reservations in this study.

This means that $n = 4$

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is $P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523$

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561$

$P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

X = 0 has the highest probability, which means that 0 is the most likely value for X.

7 0

3 years ago

The graph of g(x) is a reflection and translation of<br> f(x) = ³√x.

Kipish [7]

$g(x) = - \sqrt[3]{x - 1}$

3 0

2 years ago

Read 2 more answers

Which of the following terms correctly describe the figure given below? Check all that apply

Evgesh-ka [11]

Answer:

one of the answers is E,F

Step-by-step explanation:

I know this becuase that is a pyramid right there it is an solid but no prims or anything else on there

3 0

3 years ago

I need help and have to show my work

Oksi-84 [34.3K]

Okay
5.
m+4=17
-4 -4
m=13
6.
12=24-y
24-12
y=12
7.
15-b=12
-12 -12
b=3
8.
10t=90
90/10
t=9
9.
22/y=2
22/2
y=11
10.
54=6b
54/6
b=9

7 0

3 years ago