3 years ago

Write the Equation of a line that passes trough the pair (3,2)&(0,-4)

1 answer:

8 0

Start by finding the slope of the line by doing m(slope)=y2-y1 over x2-x1 using the pairs and then plug in the y and x of one of the points into the equation y=mx+b (y in the y and x in the x spot) and solve for b. Then plug the slope (can be a fraction shouldn’t be decimal) and y-intercept (b) back in the equation of a line above and you have your answer!

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Answer:

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Step-by-step explanation:

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3 years ago

for all values of x , a function f is defined by f(x)=x^2+7x+12 if f(a)=2, what could be the value of a?

Evgesh-ka [11]

Answer:

a = -2 or a = -5

Step-by-step explanation:

We want $f(a) = a^2 + 7a + 12 = 2$ . We can subtract 2 from both sides of this equation to get $a^2+7a+10=0$ . We can factor this to get that $(a+2)(a+5)=0$ . When the product of two numbers is equal to zero, one of the numbers must be equal to zero. This means that either a + 2 = 0, in which case a = -2, or a + 5 = 0, in which case a = -5.