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4 years ago

What is the classification for this reaction? so3 (g) + h2o (l) → h2so4 (aq)?

1 answer:

5 0

There are six common types of reactions:

1. Combination
2. Decomposition
3. Single Displacement
4. Double Displacement
5. Combustion
6. Redox

The reaction: SO₃₍g₎ + H₂O₍l₎ → H₂SO₄₍aq₎ is classified as a combination reaction. This is because for combination reactions, two (or more) reactants form a single product. On the other hand, decomposition reactions involve a single reactant breaking down into two or more simpler substances. Displacement reactions involve a more active element displacing a less active element from a compound. Meanwhile, combustion reactions involve a carbon-containing compound reacting with oxygen to form carbon dioxide and water. Redox reactions then involve exchange of electrons between species.

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Diffusion of Sucrose in Gelatin. A layer of gelatin in water 5 mm thick and con-taining 5.1 wt % gelatin at 293 K separates two

Roman55 [17]

Answer:

the flux of sucrose is 9.072 × 10⁻⁷ kg sucrose / m² sec

Explanation:

Given the data in the question;

water-gelatin solution separating two different concentration solutions of sucrose; 5.1 wt % gelatin at 293 K; at this conditions diffusivity of sucrose in water gelatin solution is;

$D_{AB}$ = 0.252 × 10⁻⁹ m²/sec.

we know that; 1 L = 0.001 m³, 1mL = 0.001 L

$C_{A1}$ = 2.0 g sucrose/100 mL = 2.0 × 10⁻³ kg sucrose / 100 × 10 ⁻³ L

$C_{A1}$ = 2.0kg sucrose / 100 L

$C_{A1}$ = 2.0 kg sucrose / 100 × 10⁻³ m³

$C_{A1}$ = 20 kg sucrose / m³

$C_{A2}$ = 0.2 g sucrose/100 mL = 0.2 × 10⁻³ kg sucrose / 100 × 10⁻³ × 10⁻³ L

$C_{A2}$ = 2 kg sucrose / m³

Thickness ß = 5 mm = 5 × 10⁻³ m

Now, flux of sucrose in kg sucrose / m³sec will be;

using the formula, $N_{A}$ = $D_{AB}$ /ß ( $C_{A1}$ - $C_{A2}$ )

we substitute

$N_{A}$ = (0.252 × 10⁻⁹ m²/sec / 5 × 10⁻³ m) ( 20 kg sucrose / m³ - 2 kg sucrose / m³ )

$N_{A}$ = (0.252 × 10⁻⁶ / 5) × 18 kg sucrose / m² sec

$N_{A}$ = 4.536 × 10⁻⁶ / 5 kg sucrose / m² sec

$N_{A}$ = 9.072 × 10⁻⁷ kg sucrose / m² sec

Therefore, the flux of sucrose is 9.072 × 10⁻⁷ kg sucrose / m² sec

4 0

3 years ago

What is the freezing point of the solution after you add an additional 1.34 g (Use i = 2.5 for MgCl2)

spayn [35]

The question is incomplete, here is the complete question:

A 50 mL solution is initially 1.52% MgCl₂ by mass and has a density of 1.05 g/mL

What is the freezing point of the solution after you add an additional 1.37 g MgCl₂? (Use i = 2.5 for MgCl₂).

Answer: The freezing point of solution is -0.808°C

Explanation:

To calculate the mass of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.05 g/mL

Volume of solution = 50 mL

Putting values in above equation, we get:

$1.05g/mL=\frac{\text{Mass of solution}}{50mL}\\\\\text{Mass of solution}=(1.05g/mL\times 50mL)=52.5g$

We are given:

Percentage of magnesium chloride in the solution = 1.52 %

Mass of magnesium chloride in the solution = 1.52 % of 52.5 g = $\frac{1.52}{100}\times 52.5=0.798g$

The equation used to calculate depression in freezing point follows:

$\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Freezing point of pure solution (water) = 0°C

i = Vant hoff factor = 2.5

$K_f$ = molal freezing point elevation constant = 1.86°C/m

$m_{solute}$ = Given mass of solute (magnesium chloride) = [0.798 + 1.34] g = 2.138 g

$M_{solute}$ = Molar mass of solute (magnesium chloride) = 95.2 g/mol

$W_{solvent}$ = Mass of solvent (water) = [52.5 - 0.798] g = 51.702 g

Putting values in above equation, we get:

$0-\text{Freezing point of solution}=1\times 1.86^oC/m\times \frac{2.138\times 1000}{95.2\times 51.702}\\\\\text{Freezing point of solution}=-0.808^oC$

Hence, the freezing point of solution is -0.808°C

5 0

3 years ago

galvanic cell is powered by the following redox reaction: (g) (aq) (l)(aq) (s) (aq) Answer the following questions about this ce

kotykmax [81]

Answer:

Explanation:

1. the 1/2 reaction that occurs at the cathode

3Cl2(g) +6e^- -------------> 6Cl^- (aq)

2 the 1/2 reaction that occurs at the anode

2MnO2(s) + 8OH^-(aq) ----------> 2MnO4^- (aq) + 4H2O(l) +6e^-

E0 = -0.59v

3Cl2(g) +6e^- -------------> 6Cl^- (aq)

E0 = 1.39v

3Cl2 (g) + 2MnO2 (s) + 8OH^(−) (aq)---------> 6Cl^(−) (aq) + 2MnO4^(−) (aq) + 4H2O (l)

E0cell = 0.80v

5 0

3 years ago

I need this asap Molar mass of C6H12O6

Zolol [24]

Answer:

180.156 g/mol

Explanation:

Hopes help

4 0

3 years ago

A student makes observations when water is added to a blue solution of copper sulfate. The student makes only 1 observation: the

horrorfan [7]

No, I believe this is not an example of a chemical reaction. What we actually see here is a physical change of the solution. Since we are adding more water to an aqueous solution which is also made up mostly of water, what we are simply basically doing is dilution. Since the solution is being diluted, so definitely the color turned lighter.

6 0

3 years ago