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3 years ago

5

What is a caustic substance?

1 answer:

Hunter-Best [27]3 years ago

8 0

However, some common household products, including drain and toilet bowl cleaners and some dishwasher detergents, contain damaging caustic substances, such as sodium hydroxide and sulfuric acid. Caustic substances (strong acids and alkalis), when swallowed, can burn the tongue, mouth, esophagus, and stomach.

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A 74 kg zebra is traveling 15 m/s east. What is the zebra’s momentum

svetoff [14.1K]

Mass × velocity = momentum

74 x 15 = momentum

7 0

3 years ago

Please explain how to do this one !! Which of the following ionic solids would have the largest lattice energy?

julsineya [31]

Answer:

I think it's Csl

I don't really know

but follow me and heart this

5 0

3 years ago

Consider the equation:

Dmitry [639]

Answer:1. $Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}$

2. The rate constant (k) for the reaction is $3.50M^\frac{-1}{2}s^{-1}$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$rate=k[CHCl_3]^x[Cl_2]^y$

k= rate constant

x = order with respect to $CHCl_3$

y = order with respect to $Cl_2$

n = x+y= Total order

1. a) From trial 1: $0.0035=k[0.010]^x[0.010]^y$ (1)

From trial 2: $0.0069=k[0.020]^x[0.010]^y$ (2)

Dividing 2 by 1 : $\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}$

$2=2^x,2^1=2^x$ therefore x=1.

b) From trial 2: $0.0069=k[0.020]^x[0.010]^y$ (3)

From trial 3: $0.0098=k[0.020]^x[0.020]^y$ (4)

Dividing 4 by 3: $\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}$

$1.4=2^y,2^{\frac{1}{2}}=2^y$ therefore $y=\frac{1}{2}$

$rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}$

2. to find rate constant using trial 1:

$0.0035=k[0.010]^1[0.010]^\frac{1}{2}$

$k=3.50M^\frac{-1}{2}s^{-1}$

5 0

3 years ago

The forensic technician at a crime scene has just prepared a luminol stock solution by adding 15.0 g of luminol into a total vol

Svet_ta [14]

The answer is in the photo

7 0

3 years ago

Let's assume you were given 2.0 g benzil, 2.2 g dibenzyl ketone, 50 mL 95% ethanol and 0.3 g potassium hydroxide to synthesize t

almond37 [142]

Answer:

the % yield is 82%

Explanation:

Given the data in the question,

we know that;

Molar mass of benzil is 210.23 g·mol−1

Molar mass of dibenzyl ketone is 210.27 g·mol−1

Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1

Now,

2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole

2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole

3.0 g of tetraphenylcyclopentadienone = 3 / 384.5 = 0.0078 mole

Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone

percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%

= 0.82 × 100%

= 82%

Therefore, the % yield is 82%

3 0

3 years ago