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Vera_Pavlovna [14]
2 years ago
11

David has a piece of wood that is 7.28 meters long. He needs 4 pieces of wood that are each 1.75 meters long. If he cuts the woo

d he has into 4 equal pieces, will each piece be long enough?
Mathematics
1 answer:
Tema [17]2 years ago
5 0

9514 1404 393

Answer:

  yes

Step-by-step explanation:

You can go at this a couple of ways:

1. The total length David needs is (1.75 m) × 4 = 7.00 m. His 7.28 m piece is long enough to provide the pieces he needs.

__

2. The length of each piece when the wood is cut into quarters is ...

  (7.28 m)/4 = 1.82 m

This is longer than the 1.75 m needed, so each piece is long enough.

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lukranit [14]

Answer:

Mrs.Harper bought 87.3 key chains which rounds up to 240.075

Step-by-step explanation:

5 0
2 years ago
What is his average speed for end the entire trip 280 miles<br> ?
-BARSIC- [3]

Answer:

20mph

Step-by-step explanation:

because when you divide the 280 it goes by 20 mph to get to 280 miles by quarters but in 20s

7 0
2 years ago
What are the first three multiples on 4 , 5 and 10
blondinia [14]

Answer:

4={4,8,12}

5={5,10,15}

10={10,20,30}

5 0
2 years ago
Read 2 more answers
A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The
disa [49]

Answer:

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

Step-by-step explanation:

The null and alternative hypothesis are given by

H0: σ₁²= σ₂² against Ha: σ₁² ≠ σ₂²

Confidence interval for the population mean difference is given by

(x`1- x`2) ± t √S²(1/n1 + 1/n2)

Where S ²= (n1-1)S₁² + S²₂(n2-1)/n1+n2-2

Critical value of t with n1+n2-2= 50+ 35-2= 83 will be -1.633

Now calculating

S ²=34* (12.8)²+ (14.6)²*49/83= 192.96

Now putting the values in the t- test

(75.1 -72.1) ± 1.633 √ 192.96(1/35 +1/50)

=3 ±  5.09

=-2.09, 8.09  is the 90 % confidence interval for the difference

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

5 0
3 years ago
Please explain and show work
Vinvika [58]
1*3/5 = 3/5.
3/5(t-6) = -0.4
Distribute 3/5
3/5t - 3.6 = -0.4
Add 3.6 
3/5t = 3.2
Divide by 3/5 
t = 5 1/3 or 5.33
6 0
3 years ago
Read 2 more answers
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