2 years ago

Can someone help with this please

Mathematics

1 answer:

DanielleElmas [232]2 years ago

4 0

What am i supposed to be answering

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Michela says that the modes of the two data are the same so the median and mean must also be the same. What is Michelaâ€™s error

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2 years ago

A scientist measure change in the temperature of chemical solution at the start of the experiment , the solutions is at temperat

zhannawk [14.2K]

Answer:

The temperature of the chemical solution after t hours is $-14.96-2.9t\;^{\circ}C$

Step-by-step explanation:

Given that the initial temperature of the chemical solution, $T_0= -14.96^{\circ}C$ .

The rate of decreasing temperature, $R = 2.9^{\circ}C/ hour$

So, after t hours, the temperature of the chemical solution will decrease by $Rt=2.9t^{\circ}C$ .

So, the temperature of the chemical solution after t hours,

$T=T_0-Rt \\\\\Rightarrow T = -14.96-2.9t\;^{\circ}C$

Hence, the temperature of the chemical solution after t hours is $-14.96-2.9t^{\circ}C$ .

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2 years ago

1. Find the distance from point P to QS

12345 [234]

Answer:

5.7 units

Step-by-step explanation:

The distance from point P to QS is the distance from point P (1, 1) to the point of interception R(-3, 5).

Use distance formula to calculate distance between P and R:

$PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$P (1, 1) = (x_1, y_1)$

$R(-3, 5) = (x_2, y_2)$

Plug in the values into the formula.

$PR = \sqrt{(-3 - 1)^2 + (5 - 1)^2}$

$PR = \sqrt{(-4)^2 + (4)^2}$

$PR = \sqrt{16 + 16}$

$PR = \sqrt{32}$

$PR = 5.7 units$ (to nearest tenth)

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3 years ago